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AWF14978
Frequent Visitor

Measure totals correct in column but not in Row

Hello,

 

I appreciate this is a common error, so please link away if there is already I thread I couldnt seem to find it.

 

I have the below function that correctly totals in the columns but does not total correctly within the rows... (See below Screenshot & Measure below)

 

Any help/Guidance would be fantastic!

 

Kind regards,

 

AF

 

AWF14978_0-1681888952578.png

 

 

 

LNS =
VAR Table1 =
    SUMMARIZE (
        Metrics,
        Metrics[Venue[VenueNameOfficial]]],
        Metrics[Business Date[Fiscal Week]]],
        "Melt", [LNS]
    )
RETURN
    SUMX ( table1, [LNS] )

 

 

1 ACCEPTED SOLUTION
v-yangliu-msft
Community Support
Community Support

Hi  @AWF14978 ,

I created some data:

vyangliumsft_0-1682402097179.png

 

Here are the steps you can follow:

1. Create measure.

Measure =
var _table1=
SUMMARIZE(
    'Table2','Table2'[Group1],"Value1",[LMS])
var _table2=
SUMMARIZE(
    'Table2','Table2'[Date],"Value2",[LMS])
return
IF(
    NOT(HASONEVALUE('Table2'[Date])),SUMX(_table2,[Value2]),
    IF(
        NOT(HASONEVALUE('Table2'[Group1])),SUMX(_table1,[Value1]),[LMS]))

2. Result:

vyangliumsft_1-1682402097180.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

View solution in original post

1 REPLY 1
v-yangliu-msft
Community Support
Community Support

Hi  @AWF14978 ,

I created some data:

vyangliumsft_0-1682402097179.png

 

Here are the steps you can follow:

1. Create measure.

Measure =
var _table1=
SUMMARIZE(
    'Table2','Table2'[Group1],"Value1",[LMS])
var _table2=
SUMMARIZE(
    'Table2','Table2'[Date],"Value2",[LMS])
return
IF(
    NOT(HASONEVALUE('Table2'[Date])),SUMX(_table2,[Value2]),
    IF(
        NOT(HASONEVALUE('Table2'[Group1])),SUMX(_table1,[Value1]),[LMS]))

2. Result:

vyangliumsft_1-1682402097180.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

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