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HI,
I have created a variable called _lastdate.
I would need another variable that shows _lastdate minus 1 month, so if _lastdate is 15 July 2022, _1month should be 15 June 2022.
Formula below gives an error message:
Solved! Go to Solution.
Hi @bsz412
Try to update your code like this:
CHrn vs Last =
Var _Lastdate= calculte(...)
Var _Last_Year = year(_Lastdate)
Var _Last_Month = month(_Lastdate)
Var _Last_Day = Day(_Lastdate)
Var _1month=Date(_Last_Year,_Last_Month-1,_Last_Day)
If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
Appreciate your Kudos!!
LinkedIn | Twitter | Blog | YouTube
Hi @bsz412
Try to update your code like this:
CHrn vs Last =
Var _Lastdate= calculte(...)
Var _Last_Year = year(_Lastdate)
Var _Last_Month = month(_Lastdate)
Var _Last_Day = Day(_Lastdate)
Var _1month=Date(_Last_Year,_Last_Month-1,_Last_Day)
If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
Appreciate your Kudos!!
LinkedIn | Twitter | Blog | YouTube
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