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SanketBhagwat
Solution Sage
Solution Sage

Create new table with one column containing all the values.

I want to create a new table with just one column containing all the values from other table.

I have 3 columns named groups, divisions and functions in one table and I want to create a new table including just one column with all the values of those 3 columns from that table.

 

If someone knows the solution,then do please let me know.

 

Regards,

Sanket Bhagwat

2 ACCEPTED SOLUTIONS
amitchandak
Super User
Super User

@SanketBhagwat , Try a new table like

union(all(Table[Name]),all(Table[group]),all(Table[division]))

 

or

 

distinct(union(all(Table[Name]),all(Table[group]),all(Table[division])))

View solution in original post

Jihwan_Kim
Super User
Super User

Hi, @SanketBhagwat 

Please check the below for creating a new table.

 

Picture2.png

 

New Table =
UNION (
VALUES ( 'Table'[Divisions] ),
VALUES ( 'Table'[Functions] ),
VALUES ( 'Table'[Groups] )
)

 

 

Hi, My name is Jihwan Kim.

 

If this post helps, then please consider accept it as the solution to help other members find it faster, and give a big thumbs up.

 

Linkedin: linkedin.com/in/jihwankim1975/

Twitter: twitter.com/Jihwan_JHKIM

If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.


Go to My LinkedIn Page


View solution in original post

2 REPLIES 2
Jihwan_Kim
Super User
Super User

Hi, @SanketBhagwat 

Please check the below for creating a new table.

 

Picture2.png

 

New Table =
UNION (
VALUES ( 'Table'[Divisions] ),
VALUES ( 'Table'[Functions] ),
VALUES ( 'Table'[Groups] )
)

 

 

Hi, My name is Jihwan Kim.

 

If this post helps, then please consider accept it as the solution to help other members find it faster, and give a big thumbs up.

 

Linkedin: linkedin.com/in/jihwankim1975/

Twitter: twitter.com/Jihwan_JHKIM

If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.


Go to My LinkedIn Page


amitchandak
Super User
Super User

@SanketBhagwat , Try a new table like

union(all(Table[Name]),all(Table[group]),all(Table[division]))

 

or

 

distinct(union(all(Table[Name]),all(Table[group]),all(Table[division])))

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