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## Count Distinct from different tables + Find matching values

Hi everyone,

Here is my sample data.

The 3 sheets are my 3 tables where the "General Info" table has all Store Names and the other 2 tables have several Store Names which have 1-to-many relationship through column "Store".

I have:

• 2 Card visuals to count distinct the number of Stores in 'NDT' & 'Laboratory'
• a "StoreName" slicer created from 'General Info' [Store]

Question 1:

Is there a way to COUNT DISTINCT the number of Stores and RETURN "0" in those 2 Cards if the selection made from the StoreName slicer does not exist in 'NDT' or 'Laboratory'?

Ex: If Z is selected from StoreName slicer, the Count result should return 0 instead of  the default (Blank)

Question 2:

a. If T is selected from the StoreName slicer and  Ultrasonic is selected from the NDT slicer, is it possible to have Power BI showed "No alternate Store can do Ultrasonic"

b. If H is selected from the StoreName slicer and STI is selected from the NDT slicer, it it possible to show:

• Count of alternatives to the selected Store = 2
• List of alternate Stores = E ; T

Can anyone please show me how to tackle this? Thank you so much!

1 ACCEPTED SOLUTION

Accepted Solutions
Super User

## Re: Count Distinct from different tables + Find matching values

Hi @trdoan,

Create the following measures:

```Distintc Count Laboratory =
IF (
DISTINCTCOUNT ( NDT[Store] ) = BLANK ();
0;
DISTINCTCOUNT ( Laboratory[Store] )
) + 0

Distintc Count NDT =
IF (
DISTINCTCOUNT ( Laboratory[Store] ) = BLANK ();
0;
DISTINCTCOUNT ( NDT[Store] )
) + 0

NDT Alternatives Count =
IF (
CALCULATE ( COUNT ( NDT[NDT] ); ALLSELECTED ( NDT[NDT] ) ) <> 1;
DISTINCTCOUNT ( NDT[Store] )
)

NDT No alternatives =
IF (
CALCULATE ( COUNT ( NDT[NDT] ); ALLSELECTED ( NDT[NDT] ) ) = 1;
"No alternate Store can do : "
& CONCATENATEX ( NDT; SELECTEDVALUE ( NDT[NDT] ); "," );
"Alternative Stores: " & CONCATENATEX ( NDT; NDT[Store]; "," )
)```

Check PBIX file attach.

Regards,

MFelix

Proud to be a Datanaut!

6 REPLIES 6
Super User

## Re: Count Distinct from different tables + Find matching values

Hi @trdoan,

Create the following measures:

```Distintc Count Laboratory =
IF (
DISTINCTCOUNT ( NDT[Store] ) = BLANK ();
0;
DISTINCTCOUNT ( Laboratory[Store] )
) + 0

Distintc Count NDT =
IF (
DISTINCTCOUNT ( Laboratory[Store] ) = BLANK ();
0;
DISTINCTCOUNT ( NDT[Store] )
) + 0

NDT Alternatives Count =
IF (
CALCULATE ( COUNT ( NDT[NDT] ); ALLSELECTED ( NDT[NDT] ) ) <> 1;
DISTINCTCOUNT ( NDT[Store] )
)

NDT No alternatives =
IF (
CALCULATE ( COUNT ( NDT[NDT] ); ALLSELECTED ( NDT[NDT] ) ) = 1;
"No alternate Store can do : "
& CONCATENATEX ( NDT; SELECTEDVALUE ( NDT[NDT] ); "," );
"Alternative Stores: " & CONCATENATEX ( NDT; NDT[Store]; "," )
)```

Check PBIX file attach.

Regards,

MFelix

Proud to be a Datanaut!

Member

## Re: Count Distinct from different tables + Find matching values

Hello @MFelix many thanks to your help! However, I noticed a few things which I've noted on the file here.

My Power BI version at work isn't up-to-date so I couldn't open your file, therefore I don't know if there're many differences in the problems I found compared to your file.

Super User

## Re: Count Distinct from different tables + Find matching values

What version are you on?

I can try and make a file in your version.

Regards,
MFelix

Proud to be a Datanaut!

Member

## Re: Count Distinct from different tables + Find matching values

@MFelix  it's September 2018. Thank you!!!

Community Support Team

## Re: Count Distinct from different tables + Find matching values

Hi @trdoan

I would suggest you to download the lastest version of Power BI which updates with more new features and fixes many issues occured in previous version.

Also it is backwords compatible. so don't worry about previous pbix files, you can use the lastest version to open and manage these.

Best Regards

Maggie

Member

## Re: Count Distinct from different tables + Find matching values

Hi @MFelix  & @v-juanli-msft , thank you for your help! MFelix's answer worked perfectly on my new version!!! Thanks again!!!