Find everything you need to get certified on Fabric—skills challenges, live sessions, exam prep, role guidance, and a 50 percent discount on exams.
Get startedEarn a 50% discount on the DP-600 certification exam by completing the Fabric 30 Days to Learn It challenge.
I need to split this by dd/mm/yyyy (UK date format).
I'm in need of an DAX formula that'll extract the date portion (02022024) of the Source Name column and then return the result in the above manner.
If someone can guide me in this, it'll be wonderful. I'm very raw with DAX.
Solved! Go to Solution.
Hi @Shak1254,
Can you please try this:
Date =
VAR DatePosition =
LEN ( Files[FileName] ) - LEN ( "ddmmyyyy" )
- LEN ( ".xlsx" ) + 1
VAR DateString =
MID ( Files[FileName], DatePosition, 8 )
RETURN
FORMAT (
DATE ( RIGHT ( DateString, 4 ), MID ( DateString, 3, 2 ), LEFT ( DateString, 2 ) ),
"dd/mm/yyyy"
)
Upvote and accept as a solution if it helps!
Hi @Shak1254,
Can you please try this:
Date =
VAR DatePosition =
LEN ( Files[FileName] ) - LEN ( "ddmmyyyy" )
- LEN ( ".xlsx" ) + 1
VAR DateString =
MID ( Files[FileName], DatePosition, 8 )
RETURN
FORMAT (
DATE ( RIGHT ( DateString, 4 ), MID ( DateString, 3, 2 ), LEFT ( DateString, 2 ) ),
"dd/mm/yyyy"
)
Upvote and accept as a solution if it helps!
You're a star! Thanks.
Hi, sorry for the very late response. I'm going to check now and get back to you.
User | Count |
---|---|
51 | |
37 | |
20 | |
14 | |
13 |
User | Count |
---|---|
96 | |
71 | |
29 | |
20 | |
13 |