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Hi All,
I Have a table containing Project Name, Stage , Start and Finish, Days to Complete ,Department
ProjectName | Task | ActualStart | ActualEnd | DaystoComplete | Department |
Test 1 | CMD | 5/16/2019 | 5/16/2019 | 0 | 1-Sol |
Test 1 | CMD | 4/23/2019 | 4/26/2019 | 3 | 1-Sol |
Test 1 | DM | 4/29/2019 | 5/2/2019 | 3 | 2-Por |
Test 1 | DM | 4/26/2019 | 5/1/2019 | 5 | 2-Por |
Test 1 | DM | 5/7/2019 | 5/10/2019 | 3 | 2-Por |
Test 1 | EF | 4/2/2019 | 4/2/2019 | 3 | 3-Test |
Test 1 | FE | 4/2/2019 | 4/2/2019 | 5 | 4-Dep |
How can i get an aggregated sum and then do an average as shown below
ProjectName | Task | ActualStart | ActualEnd | daystoComplete | Department | AggregatedSum | Average |
Test 1 | CMD | 5/16/2019 | 5/16/2019 | 0 | 1-Sol | 3 | 3 |
Test 1 | CMD | 4/23/2019 | 4/26/2019 | 3 | 1-Sol | ||
Test 1 | DM | 4/29/2019 | 5/2/2019 | 3 | 2-Por | 11 | 11 |
Test 1 | DM | 4/26/2019 | 5/1/2019 | 5 | 2-Por | ||
Test 1 | DM | 5/7/2019 | 5/10/2019 | 3 | 2-Por | ||
Test 1 | EF | 4/2/2019 | 4/2/2019 | 3 | 3-Test | 3 | 3 |
Test 1 | FE | 4/2/2019 | 4/2/2019 | 5 | 4-Dep | 3 | 3 |
Solved! Go to Solution.
@kalwabharath44 , Try two measures like
sumx(filter(allselected(Table), Table[ProjectName] = max(Table[ProjectName]) && Table[Task] = max(Table[Task])), [DaystoComplete])
AverageX(summarize(allselected(Table), Table[ProjectName], Table[Task], "_1", sum(Table[DaystoComplete])),[_1])
Hi Amit,
The Measure provided sumx(filter(allselected(Table), Table[ProjectName] = max(Table[ProjectName]) && Table[Task] = max(Table[Task])), [DaystoComplete]) did solve my problem
Thankyou for the Help !!!
Try this:
You can create a calculated summarize table summarized on ProjectName, Task and Department.
I am not sure what is the logic/granularity for your "Average" column. If it is Average of "Sum" then it should be at a higher granular level.
@kalwabharath44 , Try two measures like
sumx(filter(allselected(Table), Table[ProjectName] = max(Table[ProjectName]) && Table[Task] = max(Table[Task])), [DaystoComplete])
AverageX(summarize(allselected(Table), Table[ProjectName], Table[Task], "_1", sum(Table[DaystoComplete])),[_1])
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