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Syndicate_Admin
Administrator
Administrator

Dividir columna en filas

Tengo una columna con los siguientes datos:

RefDatos
1

20200101 - Juan Perez

El zorro marrón rápido

20200102 - Elton Hamilton

Saltó sobre el perro perezoso

2

20200103 - Jacqueline Seymour

Cuando sale el sol

20200104 - Jerry Seacrest

Y todo está bien

Quiero dividir la segunda columna en tres columnas y filas dependiendo del número de saltos de línea. Debería verse así:

RefFechaNombreComentario
120200101Juan PerezEl zorro marrón rápido
120200102Elton HamiltonSaltó sobre el perro perezoso
220200103Jacqueline SeymourCuando sale el sol
220200104Jerry SeacrestY todo está bien

¿Cómo lo haré en Power Query? Gracias...

1 ACCEPTED SOLUTION
Syndicate_Admin
Administrator
Administrator

Debería poder dividir la columna en nuevas filas usando una alimentación de línea doble y luego dividirla nuevamente en columnas usando una sola fuente de línea y luego una vez más en " - ".

let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("TY2xDoIwFAB/5aUzJqX6Aw4mhslEEwfKUOEJDfAKpVXL19saE91uuMuVJctZxgQXnOc8hw0UXhGc0OIq6dIhzF7XPdyseRLczUuSpK8ton0YnCE4qlEnkFT4ccIGzAMtuFgPag3QmJZVWcnE77RNJ1XPHgdNCGcMo/FW0rVD+oSLJ9AL+OlvuEsRWhuir2qLi5O0pwYw3oLrNLUpMb0KrKre", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Ref = _t, Data = _t]),
    #"Split Column by Delimiter" = Table.ExpandListColumn(Table.TransformColumns(Source, {{"Data", Splitter.SplitTextByDelimiter("#(lf)#(lf)", QuoteStyle.Csv), let itemType = (type nullable text) meta [Serialized.Text = true] in type {itemType}}}), "Data"),
    #"Split Column by Delimiter1" = Table.SplitColumn(#"Split Column by Delimiter", "Data", Splitter.SplitTextByDelimiter("#(lf)", QuoteStyle.Csv), {"Date-Name", "Comment"}),
    #"Split Column by Delimiter2" = Table.SplitColumn(#"Split Column by Delimiter1", "Date-Name", Splitter.SplitTextByDelimiter(" - ", QuoteStyle.Csv), {"Date", "Name"}),
    #"Changed Type" = Table.TransformColumnTypes(#"Split Column by Delimiter2",{{"Ref", Int64.Type}, {"Date", Int64.Type}, {"Name", type text}, {"Comment", type text}})
in
    #"Changed Type"

View solution in original post

2 REPLIES 2
Syndicate_Admin
Administrator
Administrator

Debería poder dividir la columna en nuevas filas usando una alimentación de línea doble y luego dividirla nuevamente en columnas usando una sola fuente de línea y luego una vez más en " - ".

let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("TY2xDoIwFAB/5aUzJqX6Aw4mhslEEwfKUOEJDfAKpVXL19saE91uuMuVJctZxgQXnOc8hw0UXhGc0OIq6dIhzF7XPdyseRLczUuSpK8ton0YnCE4qlEnkFT4ccIGzAMtuFgPag3QmJZVWcnE77RNJ1XPHgdNCGcMo/FW0rVD+oSLJ9AL+OlvuEsRWhuir2qLi5O0pwYw3oLrNLUpMb0KrKre", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Ref = _t, Data = _t]),
    #"Split Column by Delimiter" = Table.ExpandListColumn(Table.TransformColumns(Source, {{"Data", Splitter.SplitTextByDelimiter("#(lf)#(lf)", QuoteStyle.Csv), let itemType = (type nullable text) meta [Serialized.Text = true] in type {itemType}}}), "Data"),
    #"Split Column by Delimiter1" = Table.SplitColumn(#"Split Column by Delimiter", "Data", Splitter.SplitTextByDelimiter("#(lf)", QuoteStyle.Csv), {"Date-Name", "Comment"}),
    #"Split Column by Delimiter2" = Table.SplitColumn(#"Split Column by Delimiter1", "Date-Name", Splitter.SplitTextByDelimiter(" - ", QuoteStyle.Csv), {"Date", "Name"}),
    #"Changed Type" = Table.TransformColumnTypes(#"Split Column by Delimiter2",{{"Ref", Int64.Type}, {"Date", Int64.Type}, {"Name", type text}, {"Comment", type text}})
in
    #"Changed Type"
Syndicate_Admin
Administrator
Administrator

@jabrillo pregunta

¿Tu cadena se ve como

20200101 - Juan PerezThe quick brown fox 20200102 - Elton HamiltonJumped over the lazy dog

o

20200101 - Juan Perez The quick brown fox 20200102 - Elton Hamilton Jumped over the lazy dog

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