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mohammedmqi
Regular Visitor

the difference value between year

hi everyone 

i'm newbi at power bi

have this table

mohammedmqi_1-1603106156483.png

 

 

so i switch it to matrix to

 

mohammedmqi_2-1603106247456.png

and now i need to show The difference between 2019 and 2020 rahter than toatal becuse i don't need total

(differenceValue=2020-2019)

how can i do that?!

1 ACCEPTED SOLUTION
amitchandak
Super User
Super User

@mohammedmqi , create a separate year/date table and use a formula like this

 

This Year = CALCULATE(sum('Table'[Amount]),filter(ALL('Date'),'Date'[Year]=max('Date'[Year])))
Last Year = CALCULATE(sum('Table'[Amount]),filter(ALL('Date'),'Date'[Year]=max('Date'[Year])-1))

 

diff = [This Year]-[Last Year ]
diff % = divide([This Year]-[Last Year ],[Last Year ])

 

 

 

Please provide your feedback comments and advice for new videos
Tutorial Series Dax Vs SQL Direct Query PBI Tips
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View solution in original post

2 REPLIES 2
amitchandak
Super User
Super User

@mohammedmqi , create a separate year/date table and use a formula like this

 

This Year = CALCULATE(sum('Table'[Amount]),filter(ALL('Date'),'Date'[Year]=max('Date'[Year])))
Last Year = CALCULATE(sum('Table'[Amount]),filter(ALL('Date'),'Date'[Year]=max('Date'[Year])-1))

 

diff = [This Year]-[Last Year ]
diff % = divide([This Year]-[Last Year ],[Last Year ])

 

 

 

Please provide your feedback comments and advice for new videos
Tutorial Series Dax Vs SQL Direct Query PBI Tips
Appreciate your Kudos.

thanks for reply 

i use this for this yaer 

 

This Year = CALCULATE(sum(GENERALJOURNALACCOUNTENTRY[AMOUNT]),filter(ALL(GENERALJOURNALACCOUNTENTRY[DateGJ].[Year]),GENERALJOURNALACCOUNTENTRY[DateGJ].[Year]=max(GENERALJOURNALACCOUNTENTRY[DateGJ].[Year])))

 

and this last year 

Last Year = CALCULATE(sum(GENERALJOURNALACCOUNTENTRY[AMOUNT]),filter(ALL(GENERALJOURNALACCOUNTENTRY[DateGJ]),GENERALJOURNALACCOUNTENTRY[DateGJ]=max(GENERALJOURNALACCOUNTENTRY[DateGJ])-1))

 

so i need to reviw the this calculation to make sure

i'll be back after that

 

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