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San_eve
Regular Visitor

Help with strings

I have two tables. One like below with unique values up to 300 rows.

Table 1
xyz
abc
dce

I have another table table 2 with text column like below.

 

Table 2
xyz_yzx_123
def_cba_12
dce_abc_123
abc_11

 

I need o/p if the column in table 2 contains the strings in table 1. The o/p must be. I can do it with if and or but I have to manually enter 300 values. Hoping there is an easy way. Thanks.

Table 2O/p
xyz_yzx_123Yes
def_cba_12No
dce_abc_123Yes
abc_11Yes
1 ACCEPTED SOLUTION
v-cgao-msft
Community Support
Community Support

Hi @San_eve ,

 

Please create a new calculated column:

Column = 
IF (
    SUMX (
        'Table 1',
        IF (
            SEARCH ( 'Table 1'[Column1], 'Table 2'[Column1], 1, 0 ) > 0,
            1,
            0
        )
    ) > 0,
    "Yes",
    "No"
)

vcgaomsft_0-1687749914431.png

Best Regards,
Gao

Community Support Team

 

If there is any post helps, then please consider Accept it as the solution  to help the other members find it more quickly. If I misunderstand your needs or you still have problems on it, please feel free to let us know. Thanks a lot!

How to get your questions answered quickly --  How to provide sample data in the Power BI Forum

View solution in original post

2 REPLIES 2
v-cgao-msft
Community Support
Community Support

Hi @San_eve ,

 

Please create a new calculated column:

Column = 
IF (
    SUMX (
        'Table 1',
        IF (
            SEARCH ( 'Table 1'[Column1], 'Table 2'[Column1], 1, 0 ) > 0,
            1,
            0
        )
    ) > 0,
    "Yes",
    "No"
)

vcgaomsft_0-1687749914431.png

Best Regards,
Gao

Community Support Team

 

If there is any post helps, then please consider Accept it as the solution  to help the other members find it more quickly. If I misunderstand your needs or you still have problems on it, please feel free to let us know. Thanks a lot!

How to get your questions answered quickly --  How to provide sample data in the Power BI Forum

devanshi
Helper V
Helper V

Stringcontain =
FILTER(Table2, CONTAINS(Table1, Table1[ColumnName], Table2[ColumnName]))

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