Skip to main content
cancel
Showing results for 
Search instead for 
Did you mean: 

Register now to learn Fabric in free live sessions led by the best Microsoft experts. From Apr 16 to May 9, in English and Spanish.

Reply
ezolezzi92
New Member

Counting by grouping

Hi all,

 

I'm trying to come up with a formula that counts & shows the departments for each of the following IDs:

IDDepartment
101290A
103458B
101290B

 

For example, I would like to show for 101290: 2 (A & B)

 

Could someone please guide me?
Thanks in advance.

2 REPLIES 2
Anonymous
Not applicable

[Departments] =
// HASONEFILTER makes sure that you have put
// a filter on ID and only one ID is visible
// in the current context. You can also use
// HASONEVALUE but this one only makes sure
// that one value of ID is visible in the current
// context, be it through an explicit filter
// or cross-filtering.
IF( HASONEFILTER( T[ID] ),

	var __depts = VALUES( T[Department] )
	var __deptCount = COUNTROWS( __depts )
	var __output =
		if( __deptCount > 0,
			__deptCount & " (" &
			& CONCATENATEX(
				__depts,
				T[Department],
				",",
				T[Department],
				ASC)
			& ")"
		)
	return
		__output
)

 

Best

D

harshnathani
Community Champion
Community Champion

Hi @ezolezzi92 ,

 

You can create 2 measures

 

Departments = CONCATENATEX(FILTER(ALL('Table'), 'Table'[ID] = MAX('Table'[ID])),'Table'[Department],",")

 

Count of ID = COUNT('Table'[ID])

 

 

1.jpg

 

 

 

Regards,

Harsh Nathani


Appreciate with a Kudos!! (Click the Thumbs Up Button)

Did I answer your question? Mark my post as a solution!

 

Helpful resources

Announcements
Microsoft Fabric Learn Together

Microsoft Fabric Learn Together

Covering the world! 9:00-10:30 AM Sydney, 4:00-5:30 PM CET (Paris/Berlin), 7:00-8:30 PM Mexico City

PBI_APRIL_CAROUSEL1

Power BI Monthly Update - April 2024

Check out the April 2024 Power BI update to learn about new features.

April Fabric Community Update

Fabric Community Update - April 2024

Find out what's new and trending in the Fabric Community.