Match 2 tables and replace all values in first table

[gzai]

Hi,

I have 2 tables as follows : 

tracking

-------------

Agency	Estimate	Media	Remarks	Cost	Invoice	Invoice Date	Billable AR	Billable AP
ABC	P.123456	R123	R_12_A	0			0	0
ABC	P.123456	R124	R_12_B	120			0	0
BCD	P.123457	R125	R_13_A	0			0	0

outstanding

-------------

Agency	Estimate	Media	Remarks	Cost	Invoice	Invoice Date	Billable AR	Billable AP
ABC	P.123456	R124	R_12_B	120	1234567890	2024-01-01	120	0

If outstanding table contains data with same column values for "agency", "estimate", "media", "remarks" and "costs" compare it with tracking table with same columns, then data in tracking table will be updated based on latest data from outstanding table, only values in "invoice", "invoice date", "billable AR" and "billable AP" columns will be updated.

expected results : 

tracking

-------------

Agency	Estimate	Media	Remarks	Cost	Invoice	Invoice Date	Billable AR	Billable AP
ABC	P.123456	R123	R_12_A	0			0	0
ABC	P.123456	R124	R_12_B	120	1234567890	2024-01-01	120	0
BCD	P.123457	R125	R_13_A	0			0	0

Any help would be appreciated. 

Thanks in advance !

[gzai · Accepted solution]

I've found the answer,

1. using merger queries LeftOuter ( tracking table as first table, and outstanding as second table )

2. expand desired columns from outstanding table in tracking table

3. using replace value on desired column if from column expansion has a value

I don't know if there is another quick way, but this is the only way I found.

[gzai · Accepted solution]

I've found the answer,

1. using merger queries LeftOuter ( tracking table as first table, and outstanding as second table )

2. expand desired columns from outstanding table in tracking table

3. using replace value on desired column if from column expansion has a value

I don't know if there is another quick way, but this is the only way I found.

[v-heq-msft · Accepted solution]

Hi @gzai ,
There is another way to accomplish this:
1.Click append queries,

2.Remove duplicate rows

3.Final output

Best regards,

Albert He

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