Find everything you need to get certified on Fabric—skills challenges, live sessions, exam prep, role guidance, and more.
Get startedGrow your Fabric skills and prepare for the DP-600 certification exam by completing the latest Microsoft Fabric challenge.
Hi All,
I have the following table structure:
Itemgroup | Itemno |
A | 1 |
A | 2 |
A | 2 |
B | 3 |
B | 3 |
B | 3 |
C | 4 |
C | 5 |
C | 6 |
And the output I need is a calculated column that contains the unique number of Itemno for each Itemgroup.
Like this:
Itemgroup | Itemno | Unique Entries of Itemno |
A | 1 | 2 |
A | 2 | 2 |
A | 2 | 2 |
B | 3 | 1 |
B | 3 | 1 |
B | 3 | 1 |
C | 4 | 3 |
C | 5 | 3 |
C | 6 | 3 |
I think the answer would be some sort of combination of SUMMARIZE/GROUPBY and DISTINCT COUNTROWS. I just cannot figure this one out myself.
Thanks in advance!
Solved! Go to Solution.
Hi @CSRiotech ,
Here are the steps you can follow:
1. Create calculated column.
Unique Entries of Itemno =
CALCULATE(
DISTINCTCOUNT('Table'[Itemno]),
FILTER(ALL('Table'),
'Table'[Itemgroup]=EARLIER('Table'[Itemgroup])))
2. Result:
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
Hi @CSRiotech ,
Here are the steps you can follow:
1. Create calculated column.
Unique Entries of Itemno =
CALCULATE(
DISTINCTCOUNT('Table'[Itemno]),
FILTER(ALL('Table'),
'Table'[Itemgroup]=EARLIER('Table'[Itemgroup])))
2. Result:
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
User | Count |
---|---|
77 | |
74 | |
63 | |
61 | |
45 |
User | Count |
---|---|
108 | |
102 | |
93 | |
83 | |
64 |