Calculate measure for sum for each day in month

[googlogmob]

We get one sum for hole month, on first day of month

and we have to divide this sum on working days number

in my case 126500 is full sum for this month

in august are 23 working days

so I have to divide 126500 to 23 (5500)

and insert 5500 in each rows in column R, so total row will be 126500
http://prntscr.com/g96vua

Please, help me in this task

[v-chuncz-msft · Accepted solution]

@googlogmob,

A calculated column might be better.

Column =
VAR y =
    YEAR ( Table1[Date] )
VAR m =
    MONTH ( Table1[Date] )
RETURN
    IF (
        Table1[IsWorkingDay] = 1,
        DIVIDE (
            LOOKUPVALUE ( Table1[Amount], Table1[Date], DATE ( y, m, 1 ) ),
            COUNTROWS (
                FILTER (
                    Table1,
                    YEAR ( Table1[Date] ) = y
                        && MONTH ( Table1[Date] ) = m
                        && Table1[IsWorkingDay] = 1
                )
            )
        )
    )

[googlogmob]

@v-chuncz-msft, Thanks)