Register now to learn Fabric in free live sessions led by the best Microsoft experts. From Apr 16 to May 9, in English and Spanish.
Hi everyone,
I have serveral csv files that I want to transform.
I want to create a function but I m unable to define how I can Unpivot all my files:
The first row contains period of time from column4 to ColumnX (it depends on the csv)
For each csv file, Periods could be different. In this screenshot I have 201401, 201402,... But sometimes I will have 201301,201203....
When in my function, i'm unpivoting The code is :
#"Changed Type1" = Table.TransformColumnTypes(#"Promoted Headers",{{"Column1", Int64.Type}, {"NoClient", Int64.Type}, {"NoProduit", Int64.Type}, {"Values", type text}, {"201401", type text}, {"201402", type text}, {"201403", type text}, {"201404", type text}, {"201405", type text}, {"201406", type text}, {"201407", type text}, {"201408", type text}, {"201409", type text}, {"201410", type text}, {"201411", type text}}),
#"Unpivoted Other Columns" = Table.UnpivotOtherColumns(#"Changed Type1", {"Column1", "NoClient", "NoProduit", "Values"}, "Attribute", "Value")
But when I want to use my function, I have this error : Expressio.error: the column 201401 of the table was not found.
Of course due to periods which are not the same...
I think the solution will be for me to add column 4 to x in the same colum (period) and transpose the column Type ?
Thanks for helping
Solved! Go to Solution.
Perhaps try this for your Promoted Headers:
#"Promoted Headers" = Table.PromoteHeaders(Source, [PromoteAllScalars=true]),
Perhaps try this for your Promoted Headers:
#"Promoted Headers" = Table.PromoteHeaders(Source, [PromoteAllScalars=true]),
Covering the world! 9:00-10:30 AM Sydney, 4:00-5:30 PM CET (Paris/Berlin), 7:00-8:30 PM Mexico City
Check out the April 2024 Power BI update to learn about new features.
User | Count |
---|---|
104 | |
101 | |
79 | |
72 | |
64 |
User | Count |
---|---|
142 | |
108 | |
101 | |
81 | |
74 |