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Ngh25
Regular Visitor

Ranking a table based on 2 dynamic selected years using Max function

Hello @Ashish_Mathur 

I am trying to rank my Operations table based on 1 or more dynamic years chosen by the user from my Year slicer. 
This is my Operations table based on 2023 selection : 

Lab;Date;Nb_test; Rank;Rank Y-1
France;2023;5000;1;2
US;2023;602;4;5
INDIA;2023;1200;3;4

CHINA;2023;4300;2;1
BRAZIL;2023;338;5;3

2022 selection :

 

France;2022;4271;2;2
US;2022;708;5;5
INDIA;2022;2437;4;3

CHINA;2022;4980;1;1
BRAZIL;2022;2600;3;4


I want to create a measure that ensures both of the cases ( 1 or 2 selected values) and calculates the max value between both of the selected years then does the ranking this way : 

LabLims request creation dateMax (Nb tests [2023 - 2022])Max (Nb tests [2022 - 2021])Ranking [2023 - 2022]Ranking [2022 - 2021]
France[2023 - 2022]132301076311
US[2023 - 2022]9302894922
INDIA[2023 - 2022]7680732443
CHINA[2023 - 2022]6002600255
BRAZIL[2023 - 2022]8338636634

 

If anyone has a recommendation on how to achieve it, please feel free to comment below 🙂 
Thanks !

 

 
4 REPLIES 4
Ngh25
Regular Visitor

Hi @v-xinruzhu-msft  again and thank you for your answer !
1-Nb test is a measure not a column so I can"t use it directly this way! 
2- I don't see the filter on the date range here, it's only taking the max value of nb tests but the filtrer doesn't work. I did it this way : 

Max_value = CALCULATE(MAX(Nb_tests),ALLSELECTED('Operations'),'Operations'[lab] in VALUES ('Operations'[lab]))
Rank = RANKX(ALLSELECTED('Operations'[lab]),[Max_value],,DESC)
I need to use he date column from Operations based on the selected values of the calandar slicer, but I can"t achieve it correctly ! with 1 parameter it work successfully, but here, it doesn't !
Ngh25
Regular Visitor

Hi @v-xinruzhu-msft ! 
thank you for your answer but it doesn't work for me! 
The issue here, is that I am  working in direct query mode, so I can't add tables or more links in the data model, the only way I have is to do it by creating a measure! 

Hi @Ngh25 

It will not affect it, if you cannot create the table, you can use the measures I offered directly, it can work.

Max_value = CALCULATE(MAX('Table'[Nb_test]),ALLSELECTED('Table'),'Table'[Lab] in VALUES('Table'[Lab]))
Rank = RANKX(ALLSELECTED('Table'[Lab]),[Max_value],,DESC)

Output

vxinruzhumsft_0-1714438814866.png

 

Best Regards!

Yolo Zhu

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

v-xinruzhu-msft
Community Support
Community Support

Hi @Ngh25 

You can refer to the following sample.

Sample data 

vxinruzhumsft_0-1714358141248.png

1.You can create a year table, then create a relationship between tables.

vxinruzhumsft_1-1714358188619.png

vxinruzhumsft_2-1714358215625.png

 

2.Create a max measure

Max_value =
CALCULATE (
    MAX ( 'Table'[Nb_test] ),
    ALLSELECTED ( 'Table' ),
    'Table'[Lab] IN VALUES ( 'Table'[Lab] )
)

3.Create a rank measure

Rank = RANKX(ALLSELECTED('Table'[Lab]),[Max_value],,DESC)

4.Put the following fields to matrix

vxinruzhumsft_3-1714358310226.png

 

Output

vxinruzhumsft_4-1714358332033.png

 

Best Regards!

Yolo Zhu

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

 

 

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