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Hi Team
I have table like below which has multiple columns for each user for each question in the feedback form but the submitted feedback and total feedback for that particular user is same for each question is been asked. I want only one row for each user to calculate submitted feedback*100/total feedback like for first three rows it should be like 5*100/20 = 25. I would like to create a graph with the value is generating
Course ID | Country | User | startdate | submitted feedback | total feedback | Material content | Response ID | question type id | question type name |
12345 | USA | ABC | 01-01-2024 | 5 | 20 | Agree | 101 | 1 | matrix |
12345 | USA | ABC | 01-01-2024 | 5 | 20 | Yes | 690 | 5 | Yes/NO |
12345 | USA | ABC | 01-01-2024 | 5 | 20 | Great | 989 | 7 | free text |
23456 | UK | XYZ | 13-01-2024 | 8 | 15 | Yes | 830 | 2 | Yes/No |
23456 | UK | XYZ | 13-01-2024 | 8 | 15 | 120 | 5 | Freetext | |
23456 | UK | XYZ | 13-01-2024 | 8 | 15 | Great | 678 | 7 | Matrix |
56788 | USA | HK | 02-02-2024 | 5 | 10 | Yes | 160 | 5 | Yes/NO |
56788 | USA | HK | 02-02-2024 | 5 | 10 | Great | 128 | 7 | Matrix |
78901 | UK | AK | 09-02-2024 | 8 | 30 | Yes | 678 | 1 | Yes/NO |
Solved! Go to Solution.
Hi, @Arundathi
You can then use group by in PowerQuery to achieve the effect you want. Select the desired columns
And click Group By
Close and apply, then create a new column:
Feedback Percentage = [submitted feedback]*100/[total feedback]
Here is my preview:
How to Get Your Question Answered Quickly
Best Regards
Yongkang Hua
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi, @Arundathi
You can then use group by in PowerQuery to achieve the effect you want. Select the desired columns
And click Group By
Close and apply, then create a new column:
Feedback Percentage = [submitted feedback]*100/[total feedback]
Here is my preview:
How to Get Your Question Answered Quickly
Best Regards
Yongkang Hua
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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