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Hola amigos.
Intento crear una columna mediante DAX, creando específicamente una columna de índice utilizando otras columnas como condicionales. A continuación pongo una imagen.
Espero que puedas ayudarme.
saludos.
Solved! Go to Solution.
@rmcneish , Intentar como nueva columna
countx(filter,Table,[place] á earlier([place]) && [date] á earlier([date]) && [time] <-earlier([time]),[time])
O
countx(filter,Table,[place] á earlier([place]) && [time] <-earlier([time]),[time])
Hola, @rmcneish , es posible que desee probar
Index = RANKX(FILTER(Table1,Table1[PLACE]=EARLIER(Table1[PLACE])),Table1[DATE]+Table1[HOUR])
Thanks to the great efforts by MS engineers to simplify syntax of DAX! Most beginners are SUCCESSFULLY MISLED to think that they could easily master DAX; but it turns out that the intricacy of the most frequently used RANKX() is still way beyond their comprehension! |
DAX is simple, but NOT EASY! |
@rmcneish , Intentar como nueva columna
countx(filter,Table,[place] á earlier([place]) && [date] á earlier([date]) && [time] <-earlier([time]),[time])
O
countx(filter,Table,[place] á earlier([place]) && [time] <-earlier([time]),[time])
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