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rmcneish
Helper I
Helper I

¿Cómo crear una nueva columna con un índice por otras columnas con DAX?

Hola amigos.

Intento crear una columna mediante DAX, creando específicamente una columna de índice utilizando otras columnas como condicionales. A continuación pongo una imagen.

Espero que puedas ayudarme.

DAX ORDER.jpg

saludos.

1 ACCEPTED SOLUTION
amitchandak
Super User
Super User

@rmcneish , Intentar como nueva columna

countx(filter,Table,[place] á earlier([place]) && [date] á earlier([date]) && [time] <-earlier([time]),[time])

O

countx(filter,Table,[place] á earlier([place]) && [time] <-earlier([time]),[time])

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2 REPLIES 2
CNENFRNL
Community Champion
Community Champion

Hola, @rmcneish , es posible que desee probar

Index = RANKX(FILTER(Table1,Table1[PLACE]=EARLIER(Table1[PLACE])),Table1[DATE]+Table1[HOUR])

Screenshot 2020-12-05 034700.png


Thanks to the great efforts by MS engineers to simplify syntax of DAX! Most beginners are SUCCESSFULLY MISLED to think that they could easily master DAX; but it turns out that the intricacy of the most frequently used RANKX() is still way beyond their comprehension!

DAX is simple, but NOT EASY!

amitchandak
Super User
Super User

@rmcneish , Intentar como nueva columna

countx(filter,Table,[place] á earlier([place]) && [date] á earlier([date]) && [time] <-earlier([time]),[time])

O

countx(filter,Table,[place] á earlier([place]) && [time] <-earlier([time]),[time])

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