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Friends, I try to call one function in to the other kind of nested.
M-Code:
let
ADD = (x as any) => let s2 = x+1
in
s2,
SUB = let s33 = ADD -1
in
s33
in
SUB
ERROR:
Thanks in advance
@Greg_Deckler @watkinnc Many thanks both of you. The below code is working fine to me
let
ADD = (x as any) => let s2 = x+4
in
s2,
SUB =(x as any) => let s33 = ADD(x) -3
in
s33
in
SUB
@msksenthil I would still do it as 2 functions:
let
ADD = (x as any) => let s2 = x+1
in
s2
in
ADD
let
SUB = (x as any) => let s33 = ADD(x)-1
in
s33
in
SUB
You need to complete your ADD function. After you have in s2 , you have to write in ADD. right now, ADD is unevaluated function -1.
@msksenthil Perhaps I'm mistaken but don't you want 2 separate functions:
let
ADD = (x as any) => let s2 = x+1
in
s2
in
ADD
let
SUB = (x as any) => let s33 = x+1
in
s33
in
SUB
Nope, I try to use the result of the previous 'let' in the following 'let'
Instead of "in s2", try "in s2 in ADD".
--Nate
Sorry, I didn't get you
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