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Helper II

## Help with RANX formula and date buckets

Hi all,

I have a table containing complaints recieved. These have a date attached to them which has been broken down in the table in a heirarchical structure.

I am trying to bucket these dates into the following buckets :

0 - 4 weeks

4 - 8 weeks

8 + Weeks

I have taken the month number and Ranked them using the following formula :

T_Date = RANKX(DateTable,[Month Num],,ASC,Dense)-1

From there, I have bucketed them using the following :

Open Complaints Buckets = If(DateTable[T_Date]=1, "0 - 4 Weeks",
If(DateTable[T_Date]=2, "4 - 8 Weeks", "8+ Weeks"))

Unfortunately when doing the above, i get the following :

Please can you advise where I have gone wrong and how to correct this?

Regards,

Indy

1 ACCEPTED SOLUTION
Community Support

Hi @indyb

Please check If this result is expected.

Create a new table

date =
CALENDARAUTO (),
"year", YEAR ( [Date] ),
"month", MONTH ( [Date] ),
"monthno", FORMAT (
[Date],
"yyyymm"
),
"monthname", FORMAT (
[Date],
"Mmm yyyy"
)
)

rank = RANKX(FILTER('date','date'[Date]<=TODAY()),[monthno],,DESC,Dense)-1

rank bucket = SWITCH([rank],1,"0~4 weeks",2,"4~8 weeks","8+weeks")

Best Regards
Maggie
Community Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

3 REPLIES 3
Community Support

Hi @indyb

Please check If this result is expected.

Create a new table

date =
CALENDARAUTO (),
"year", YEAR ( [Date] ),
"month", MONTH ( [Date] ),
"monthno", FORMAT (
[Date],
"yyyymm"
),
"monthname", FORMAT (
[Date],
"Mmm yyyy"
)
)

rank = RANKX(FILTER('date','date'[Date]<=TODAY()),[monthno],,DESC,Dense)-1

rank bucket = SWITCH([rank],1,"0~4 weeks",2,"4~8 weeks","8+weeks")

Best Regards
Maggie
Community Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Helper II

Thank you so much @v-juanli-msft !

That worked for me!

Super User IV

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