Formula.Firewall error

[Anonymous]

Hi everyone, I need help with a power query in the editor. I have added a new column in a table with a web.content query where it gives me the error message Formula.Firewall error. here is the Code

Quelle = #"ARTICLE SALES",
        #"Andere entfernte Spalten" = Table.SelectColumns(Quelle,{"Modell", "Lieferantenfarbe", "Modellbezeichnung", "Product ID"}),
        #"Entfernte Duplikate" = Table.Distinct(#"Andere entfernte Spalten", {"Product ID"}),
        #"Hinzugefügte benutzerdefinierte Spalte" = Table.AddColumn(#"Entfernte Duplikate", "Img URL", 
            each Json.Document(
                    Web.Contents("https://hostname.app.de/getImageURLBySKU?sku="[Product ID])
                )),
        #"Erweiterte Img URL" = Table.ExpandRecordColumn(#"Hinzugefügte benutzerdefinierte Spalte", "Img URL", {"result"}, {"Img URL.result"}),
        #"Umbenannte Spalten" = Table.RenameColumns(#"Erweiterte Img URL",{{"Img URL.result", "Img URL"}})
    in
        #"Umbenannte Spalten"

The result of what the query Json.Document(Web.Contents()) returns as a single query is

let
        Source = 
            Json.Document(
                Web.Contents("https://hostname.app.de/rest/unprotected/files/images/products/getImageURLBySKU?sku=[Product ID])
            ),
            
    imageURL = Source[result]
    in
        imageURL

 https://test.hostname.de/media/catalog/product/m/o/803040-107-1.jpg

I need the result of the Json. document for each individual Product ID in the new column

Does anyone have an idea how I put the query Json.Document(Web.Contents()) outside the new query columns and get the result for each ID

[Jimmy801 · Accepted solution]

hello @Anonymous 

okay, than these request has nothing to do with an Firewall-error. 

Change your query into a function and invoke it in a new custom column and passing the product id

Function name. 

//GetProductImage
(productid) =
let
        Source = 
            Json.Document(
                Web.Contents("https://hostname.app.de/rest/unprotected/files/images/products/getImageURLBySKU?sku=[" & productid & "])
            ),
            
    imageURL = Source[result]
    in
        imageURL

and in your table invoke it in a new column like this

GetProductImage( [Product ID])

If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
Kudoes are nice too

Have fun

Jimmy

[v-juanli-msft]

Hi @Anonymous 

As tested, i can't access your url.

Check if the articles help you.

https://blog.crossjoin.co.uk/2018/08/30/power-bi-extract-urls-web-page/

https://radacad.com/get-images-from-web-page-into-the-power-bi-report-using-power-query

Best Regards
Maggie
Community Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[Anonymous]

To better understand what I want. The result of the query returns the correct image URL.

let
        Source = 
            Json.Document(
                Web.Contents("https://hostname.app.de/rest/unprotected/files/images/products/getImageURLBySKU?sku=[Product ID])
            ),
            
    imageURL = Source[result]
    in
        imageURL

https://test.hostname.de/media/catalog/product/m/o/803040-107-1.jpg

I need the result of the query for each row of product ID in my article table. So I always get a different image URL as result for each Product ID. I don't know how to write this query correctly without getting the message Formula.Firewall error

[Jimmy801 · Accepted solution]

hello @Anonymous 

okay, than these request has nothing to do with an Firewall-error. 

Change your query into a function and invoke it in a new custom column and passing the product id

Function name. 

//GetProductImage
(productid) =
let
        Source = 
            Json.Document(
                Web.Contents("https://hostname.app.de/rest/unprotected/files/images/products/getImageURLBySKU?sku=[" & productid & "])
            ),
            
    imageURL = Source[result]
    in
        imageURL

and in your table invoke it in a new column like this

GetProductImage( [Product ID])

If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
Kudoes are nice too

Have fun

Jimmy

[Anonymous]

Hi Jimmy, thanks for your suggestions. I did a small adjustment and the function works fine. 

(ProductSKU as text) =>
let
        Source = 
            Json.Document(
                Web.Contents("https://hostname.app.de/rest/unprotected/files/images/products/getImageURLBySKU?sku=" & (ProductSKU) )
            ),
            
    imageURL = Source[result]
    in
        imageURL

After this i put the function in my test table and it works fine for each Product ID

let
    Quelle = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMjI1NDSxsDC2MI03MY53cQzyjnfyCXVVitWJVrKMMjUFypmYAOWM4n09XcBS8aHBri5g+ZB4Y5N4QwMDy/jixLSixDywYLB3vIFRvJGBgWF8Uk5icrZ+flpafHlGZkmqUmwsAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type text) meta [Serialized.Text = true]) in type table [#"Product ID" = _t]),
    #"Geänderter Typ" = Table.TransformColumnTypes(Quelle,{{"Product ID", type text}}),
    #"Hinzugefügte benutzerdefinierte Spalte1" = Table.AddColumn(#"Geänderter Typ", "URLWithParameter(ProductID)", each IMGUrlwithParameterAsText([Product ID]))
in
    #"Hinzugefügte benutzerdefinierte Spalte1"

After this test, i have integrate the function in my origin Sales table an the error massage are displayed: Formula.Firewall: Abfrage 'ARTICLE SALES (2)' (Schritt 'Hinzugefügte benutzerdefinierte Spalte') greift auf Datenquellen mit Sicherheitsstufen zu, die nicht zusammen verwendet werden können. Erstellen Sie diese Datenkombination neu. 

Do you have an idea, how i get this to work for an existing query with an query from an folder.files

let
    Quelle = Folder.Files("R:\mycompany\bireporting\02-BI-DATA\\08-ARTICLE-SALES"),
    #"Andere entfernte Spalten" = Table.SelectColumns(Quelle,{"Content"}),
    #"Gefilterte ausgeblendete Dateien1" = Table.SelectRows(#"Andere entfernte Spalten", each [Attributes]?[Hidden]? <> true),
    #"Benutzerdefinierte Funktion aufrufen1" = Table.AddColumn(#"Gefilterte ausgeblendete Dateien1", "Datei transformieren", each #"Datei transformieren"([Content])),
    #"Andere entfernte Spalten1" = Table.SelectColumns(#"Benutzerdefinierte Funktion aufrufen1", {"Datei transformieren"}),
    #"Erweiterte Datei transformieren" = Table.ExpandTableColumn(#"Andere entfernte Spalten1", "Datei transformieren", {"Modell"}, {"Datei transformieren.Modell"}),
    #"Hinzugefügte benutzerdefinierte Spalte" = Table.AddColumn(#"Erweiterte Datei transformieren", "IMGURL", each IMGUrlwithParameterAsText([Datei transformieren.Modell]))
in
    #"Hinzugefügte benutzerdefinierte Spalte"

[Jimmy801]

Hello @Anonymous 

you have to put everything in one single query. This what I've suggested you in my first post

If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
Kudoes are nice too

Have fun

Jimmy

[Anonymous]

Okay. Thank you @Jimmy801 . Please show me how to put everything into one query. It's not working for me.

//IMGUrlwithParameterAsText --------> this is my function
(ProductSKU as text) =>
        Source = 
            Json.Document(
     Web.Contents("https://ista.mf1832.de/ista/rest/unprotected/files/images/products/getImageURLBySKU?sku=" & (ProductSKU) )
            ),
    imageURL = Source[result]
        imageURL

let
//ArticleSalesQuery --------> this is my query

    Quelle = Folder.Files("R:\MyCompany\bireporting\02-BI-DATA\08-ARTICLE-SALES"),
    #"Andere entfernte Spalten" = Table.SelectColumns(Quelle,{"Content"}),
    #"Gefilterte ausgeblendete Dateien1" = Table.SelectRows(#"Andere entfernte Spalten", each [Attributes]?[Hidden]? <> true),
    #"Benutzerdefinierte Funktion aufrufen1" = Table.AddColumn(#"Gefilterte ausgeblendete Dateien1", "Datei transformieren", each #"Datei transformieren"([Content])),
    #"Andere entfernte Spalten1" = Table.SelectColumns(#"Benutzerdefinierte Funktion aufrufen1", {"Datei transformieren"}),
    #"Erweiterte Datei transformieren" = Table.ExpandTableColumn(#"Andere entfernte Spalten1", "Datei transformieren", {"Modell"}, {"Datei transformieren.Modell"}),
    #"Umbenannte Spalten" = Table.RenameColumns(#"Erweiterte Datei transformieren",{{"Datei transformieren.Modell", "Product ID"}}),
    #"Aufgerufene benutzerdefinierte Funktion" = Table.AddColumn(#"Umbenannte Spalten", "ImgUrl", each IMGUrlwithParameterAsText([Product ID]))
in
    #"Aufgerufene benutzerdefinierte Funktion"

[Jimmy801 · Accepted solution]

Hello @Anonymous 

I've just checked your error message again, and it seems that the error is caused due to different settings of your data sources. So please try to go go Datasourcesettings (Datenquelleneinstellungen) and set the same settings for every data source (public i suppose). This should solve your problem.

All the best

Jimmy

[Anonymous]

this query triggers the error message. 

#"Hinzugefügte benutzerdefinierte Spalte" = Table.AddColumn(#"Entfernte Duplikate", "Img URL", 
            each Json.Document(
                    Web.Contents("https://hostname.app.de/getImageURLBySKU?sku="[Product ID])
                )),

 If I set the privacy settings under options to ignore, the query works.

[Jimmy801]

Hello @Anonymous 

I know, so if you want to make it work without changing this important setting, put everything in one query

Jimmy

[Jimmy801]

Hello @Anonymous 

You didn't post the exact firewall error but the Firewall.Error is triggered most proababy because you are referencing to another partition here:

Quelle = #"ARTICLE SALES",

Try to include this query into your main query, then it should work

If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
Kudoes are nice too

Have fun

Jimmy