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KG1
Helper II
Helper II

Custom Matrix - help needed

Hi

I need to be able to create a matrix like this which plots a value inside a matrix based on its score.

Could anyone offer some advice as to whether this would be possible and how it can be done?

Many ThanksHeatmap.JPG

 

1 ACCEPTED SOLUTION
v-shex-msft
Community Support
Community Support

Hi @KG1,

I don't think you can do customize with matrix plot features.
For your scenario, I'd like to suggest you write a measure with if statement to check current row and column label to find out the score, then you can replace this score to other values based on condition.

Measure =
VAR currRowLable =
    SELECTEDVALUE ( Table[Row] )
VAR currColLable =
    SELECTEDVALUE ( Table[Column] )
VAR _score =
    CALCULATE (
        SUM ( Table[Score] ),
        FILTER (
            ALLSELECTED ( Table ),
            [Column] IN currColLable
                && [Row] IN currRowLable
        )
    )
RETURN
    IF ( _score > 10, 2, IF ( _score < 10 && _score > 5, 1, 0 ) )

Regards,

Xiaoxin Sheng

Community Support Team _ Xiaoxin
If this post helps, please consider accept as solution to help other members find it more quickly.

View solution in original post

1 REPLY 1
v-shex-msft
Community Support
Community Support

Hi @KG1,

I don't think you can do customize with matrix plot features.
For your scenario, I'd like to suggest you write a measure with if statement to check current row and column label to find out the score, then you can replace this score to other values based on condition.

Measure =
VAR currRowLable =
    SELECTEDVALUE ( Table[Row] )
VAR currColLable =
    SELECTEDVALUE ( Table[Column] )
VAR _score =
    CALCULATE (
        SUM ( Table[Score] ),
        FILTER (
            ALLSELECTED ( Table ),
            [Column] IN currColLable
                && [Row] IN currRowLable
        )
    )
RETURN
    IF ( _score > 10, 2, IF ( _score < 10 && _score > 5, 1, 0 ) )

Regards,

Xiaoxin Sheng

Community Support Team _ Xiaoxin
If this post helps, please consider accept as solution to help other members find it more quickly.

View solution in original post

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