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Guyakobov Regular Visitor
Regular Visitor

previous value

HI,

 

I would like to get the previous value.

so when I choose date 12.03.18 my profit will be -123960.45 and not -116778.37

http://prntscr.com/mtzgw5

 

Thanks 

8 REPLIES 8
Super User
Super User

Re: previous value

@Guyakobov  Please try this as a New Measure

 

Test231 = 
VAR _PrevMax = CALCULATE(MAX(Test231PrevValDynamic[Time]),FILTER(ALL(Test231PrevValDynamic),Test231PrevValDynamic[Time]<SELECTEDVALUE(Test231PrevValDynamic[Time])))
RETURN CALCULATE(FIRSTNONBLANK(Test231PrevValDynamic[Profit],0),Test231PrevValDynamic[Time] = _PrevMax)

image.png



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Guyakobov Regular Visitor
Regular Visitor

Re: previous value

HI,

 

i wrote the measure like this : 

floating pl is the table name.

 

Test231 =
VAR _PrevMax = CALCULATE(MAX('floating pl'[Time]),FILTER(ALL('floating pl'),'floating pl'[Time]<SELECTEDVALUE('floating pl'[Time])))
RETURN CALCULATE(FIRSTNONBLANK('floating pl'[Profit],0),'floating pl'[Time] = _PrevMax)

 

 And my measure is null http://prntscr.com/mu15sc 

 

BTW, there is more than one Login account.

 

Thanks 

 

Super User
Super User

Re: previous value

@Guyakobov  You are using date filter as range instead of list, as your requirement is to show the previous profit value based on the date selected. Also, use Login in your filter criteria if you want to include Login in the logic as below

 

Test231 = 
VAR _PrevMax = 
CALCULATE(MAX(Test231PrevValDynamic[Time]),FILTER(ALL(Test231PrevValDynamic),Test231PrevValDynamic[Time]<SELECTEDVALUE(Test231PrevValDynamic[Time]) && Test231PrevValDynamic[Login] = SELECTEDVALUE(Test231PrevValDynamic[Login]) ))
RETURN CALCULATE(FIRSTNONBLANK(Test231PrevValDynamic[Profit],0),Test231PrevValDynamic[Time] = _PrevMax)

image.pngimage.png



Did I answer your question? Mark my post as a solution !

Proud to be a Datanaut !





Guyakobov Regular Visitor
Regular Visitor

Re: previous value

Hi,

 

I want to use the slicer so the start date will show the previous value - im not gonna use the date picker.

 

I tried the new formula and still blank http://prntscr.com/mu2ifa 

 

Test231 =
VAR _PrevMax =
CALCULATE(MAX('floating pl'[Time]),FILTER(ALL('floating pl'),'floating pl'[Time]<SELECTEDVALUE('floating pl'[Time]) && 'floating pl'[Login] = SELECTEDVALUE('floating pl'[Login]) ))
RETURN CALCULATE(FIRSTNONBLANK('floating pl'[Profit],0),'floating pl'[Time] = _PrevMax)

 

 

Community Support Team
Community Support Team

Re: previous value

Hi @Guyakobov ,

 

You should select Login too. Or SELECTEDVALUE('floating pl'[Login])  is blank. Please give it a try.

 

 

Best Regards,

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Guyakobov Regular Visitor
Regular Visitor

Re: previous value

HI,

 

still doesn't work, I want a column that will give me the previous row with separation from each account.

 

http://prntscr.com/mulbdm

 

Thanks 

Community Support Team
Community Support Team

Re: previous value

Hi @Guyakobov ,

 

You mean you need a calculated column. If so, you can't make it dynamic with a slicer. Please try out the formula below as a calculated column.

 

Previous =
VAR currentAccount = [account]
VAR currentTime = [time]
VAR previousDate =
    CALCULATE (
        MAX ( 'table'[time] ),
        FILTER (
            'table',
            'table'[account] = currentAccount
                && 'table'[time] < currenttime
        )
    )
RETURN
    CALCULATE (
        SUM ( 'table'[profit] ),
        FILTER (
            'table',
            'table'[account] = currentAccount
                && 'table'[time] = previousDate
        )
    )

 

 

Best Regards,

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Community Support Team
Community Support Team

Re: previous value

Hi @Guyakobov ,

 

Could you please mark the proper answers as solutions?

 

 

 

Best Regards,

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.