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formula help status

Hi there ;

 

i have a column which shows "day" value as below left , i would like to create a new column that  writing  status according to below rule

 

İf day column value is between -3 and +3 status = on time 

if day column is bigger than  +3 status is = late

if day column is smaller than -3 status is early

 

thanks in advance 

 

dayStatus
0On time
3On time
5Late
2On time
1On time
-6Early
-4Early
-3On time
-1On time
1 ACCEPTED SOLUTION

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Super User II
Super User II

Re: formula help status

Hi @erhan_79 

Status Column = 
SWITCH(TRUE(),
[day] < -3, "early",
[day] > 3, "late",
"on time"
)

do not hesitate to give a kudo to useful posts and mark solutions as solution
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2 REPLIES 2
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Super User II
Super User II

Re: formula help status

Hi @erhan_79 

Status Column = 
SWITCH(TRUE(),
[day] < -3, "early",
[day] > 3, "late",
"on time"
)

do not hesitate to give a kudo to useful posts and mark solutions as solution
LinkedIn

View solution in original post

Highlighted
Post Patron
Post Patron

Re: formula help status

Hi @az38 ;

 

you are perfect ! it is working thank you!

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