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Frequent Visitor

## count rows with multiple condition

Hi

i have two tables here below. From the first table, i want to count the opp no. but just status of won,open and lost.

Then I want to calculate the average no. of opportunity by month (of just won, open and lost) by distinct count the "month/year" from date table so I can visualise the number as a card visual.   Please help me with this!

I want to count the number of opportunity id of just open, lost and in porocessDates table

1 ACCEPTED SOLUTION

Accepted Solutions
Frequent Visitor

## Re: count rows with multiple condition

I instead found out the funciton.

total opp = CALCULATE(COUNT('Opportunity'[Opp number]),'Opportunity'[Status]IN{"won","lost","did not proceed"})

Thanks.

3 REPLIES 3
Community Support Team

## Re: count rows with multiple condition

Hi @megan2010,

If you only want to calculate the count of opportunity id of open, lost and in porocess.

You have two ways to achieve that.

1. Drag the Status column to filed and select Count.

Then unclick Won under visual level filter as below.

2. Create the measure directly.

```Count =
CALCULATE (
COUNT ( 'Table1'[Opp no] ),
FILTER ( 'Table1', 'Table1'[Status] <> "Won" )
)
```

If you want to calculate the average no. of opportunity by month, I'm afraid that you should have a relationship between the two tables, but I cannot find the date column in your first table so it seems that we cannot create the relationship between the two tables.

Best  Regards,

Cherry

Community Support Team _ Cherry Gao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Community Support Team

## Re: count rows with multiple condition

Hi @megan2010 ,

If you have solved, please accept the replies making sense as solution to your question so that people who may have the same question can get the solution directly.

Best  Regards,

Cherry

Community Support Team _ Cherry Gao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Frequent Visitor