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Anonymous
Not applicable

count number of occurrences of a field over all rows in a table in query editor

Hi there, 

Can someone outline how I would write the equivalent in query editor of below excel example? 

I know how to write this in a measure or by adding a calculated column, but I'd prefer to do so in query editor to allow subsequent logic to work properly. 

 

thanks!

 

countif.PNG

1 ACCEPTED SOLUTION
tex628
Community Champion
Community Champion

I apologize, i have a habit of not reading things properly 🙂

Try this as a custom column in queryeditor instead:

List.Count(
    Table.SelectRows(
       #"Previous step is supposed to be here",
        (C) => [Abc] = C[Abc]
    )[Abc]
)

It works fine for me:
image.png

More info @ https://stackoverflow.com/questions/53305097/countifs-equivalent-in-power-query-m-counts-per-row-wit...


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5 REPLIES 5
tex628
Community Champion
Community Champion

Column = CALCULATE(COUNTROWS(Table1),ALL(Table1),Table1[Column1] = EARLIER(Table1[Column1]))

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Anonymous
Not applicable

@tex628 

thanks for this, but are you sure this is meant to work in query editor?  I'm getting error message, first with 'Calculate' and the with 'countrows'. I'm looking for a solution in the query editor environment for my question. 

thanks

tex628
Community Champion
Community Champion

I apologize, i have a habit of not reading things properly 🙂

Try this as a custom column in queryeditor instead:

List.Count(
    Table.SelectRows(
       #"Previous step is supposed to be here",
        (C) => [Abc] = C[Abc]
    )[Abc]
)

It works fine for me:
image.png

More info @ https://stackoverflow.com/questions/53305097/countifs-equivalent-in-power-query-m-counts-per-row-wit...


Connect on LinkedIn

I am sorry to ask 5 years later.. 

 

Your solution is magnificent and work perfectly, but how can I use this solution if I have multiple criteria? If I want to count if column a AND column b have the same value as the current row. 

 

Hope you can help, as I have had trouble finding the correct syntax. 

 

Thank you very much in advance. 

Anonymous
Not applicable

@tex628 thanks! this seems to work, albeit not the fastest of solutions.... 😞  but happy it''s working though. I'm not suggesting I fully understand its logic, but for now, I'm happy to be able to proceed. 

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