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srivally
Helper I
Helper I

consistent top customers

Hi All,

Can anyone help me on finding consistent top customers for last 3 years.

Regards,

Srivalli

2 ACCEPTED SOLUTIONS
v-frfei-msft
Community Support
Community Support

Hi @srivally,

 

I made one sample for your reference, if it doesn't meet your requirement, kindly share your sample data and excepted result to me.

 

Here we need to create two measures to work on it.

 

countlast = CALCULATE(COUNTA(Table1[customers]),FILTER(Table1,Table1[date]<=TODAY() && Table1[date]>=DATE(YEAR(TODAY())-3,MONTH(TODAY()),DAY(TODAY()))))
Measure = TOPN(1,VALUES(Table1[customers]),[countlast])

Capture.PNG

 

Regards,

Frank

Community Support Team _ Frank
If this post helps, then please consider Accept it as the solution to help the others find it more quickly.

View solution in original post

Hi @srivally,

 

Does that make sense? If so, kindly mark the answer as solution to close the case.


Regards,
Frank

Community Support Team _ Frank
If this post helps, then please consider Accept it as the solution to help the others find it more quickly.

View solution in original post

2 REPLIES 2
v-frfei-msft
Community Support
Community Support

Hi @srivally,

 

I made one sample for your reference, if it doesn't meet your requirement, kindly share your sample data and excepted result to me.

 

Here we need to create two measures to work on it.

 

countlast = CALCULATE(COUNTA(Table1[customers]),FILTER(Table1,Table1[date]<=TODAY() && Table1[date]>=DATE(YEAR(TODAY())-3,MONTH(TODAY()),DAY(TODAY()))))
Measure = TOPN(1,VALUES(Table1[customers]),[countlast])

Capture.PNG

 

Regards,

Frank

Community Support Team _ Frank
If this post helps, then please consider Accept it as the solution to help the others find it more quickly.

Hi @srivally,

 

Does that make sense? If so, kindly mark the answer as solution to close the case.


Regards,
Frank

Community Support Team _ Frank
If this post helps, then please consider Accept it as the solution to help the others find it more quickly.

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