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consistent top customers

Hi All,

Can anyone help me on finding consistent top customers for last 3 years.

Regards,

Srivalli

2 ACCEPTED SOLUTIONS

Accepted Solutions
Community Support Team

Re: consistent top customers

Hi @srivally,

I made one sample for your reference, if it doesn't meet your requirement, kindly share your sample data and excepted result to me.

Here we need to create two measures to work on it.

`countlast = CALCULATE(COUNTA(Table1[customers]),FILTER(Table1,Table1[date]<=TODAY() && Table1[date]>=DATE(YEAR(TODAY())-3,MONTH(TODAY()),DAY(TODAY()))))`
`Measure = TOPN(1,VALUES(Table1[customers]),[countlast])`

Regards,

Frank

Community Support Team _ Frank
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Highlighted
Community Support Team

Re: consistent top customers

Hi @srivally,

Does that make sense? If so, kindly mark the answer as solution to close the case.

Regards,
Frank

Community Support Team _ Frank
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
2 REPLIES 2
Community Support Team

Re: consistent top customers

Hi @srivally,

I made one sample for your reference, if it doesn't meet your requirement, kindly share your sample data and excepted result to me.

Here we need to create two measures to work on it.

`countlast = CALCULATE(COUNTA(Table1[customers]),FILTER(Table1,Table1[date]<=TODAY() && Table1[date]>=DATE(YEAR(TODAY())-3,MONTH(TODAY()),DAY(TODAY()))))`
`Measure = TOPN(1,VALUES(Table1[customers]),[countlast])`

Regards,

Frank

Community Support Team _ Frank
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Highlighted
Community Support Team

Re: consistent top customers

Hi @srivally,

Does that make sense? If so, kindly mark the answer as solution to close the case.

Regards,
Frank

Community Support Team _ Frank
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.