Value difference by Date and categorial variable

[Anonymous]

Hi all

I want to calculate the difference between values, based on the date as well as another categorial variable.

All that should be displayed in a waterfall diagram (column Expected Result). I attached a screenshot with dummy data and the expectet outcome.

Thanks in advance!

 

[Ashish_Mathur]

Hi,

Try this calculated column formula

=data[value]-lookupvalue(data[value],data[date],calculate(max(data[date]),filter(data,data[cat]=earlier(data[cat])&&data[date]<earlier(data[date]))),data[cat],data[cat])

Hope this helps.

[v-yuaj-msft · Accepted solution]

Hi @Anonymous ，

Based on your description, you can do some steps as follows.

1. Create a column to mark month.

Month = MONTH('Diff'[Date])

2.  Create a new measure.

Test Value =

var x1=MAXX(FILTER(ALL(Diff),[Month]=SELECTEDVALUE(Diff[Month])&&'Diff'[Cat]=SELECTEDVALUE(Diff[Cat])),'Diff'[Value])

var x2=MAXX(FILTER(ALL(Diff),[Month]=SELECTEDVALUE(Diff[Month])-1&&'Diff'[Cat]=SELECTEDVALUE(Diff[Cat])),'Diff'[Value])

return

x1-x2

Result:

Hope that's what you were looking for.

Best Regards,

Yuna

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[Anonymous]

Hi, thank you very much for your help!! It worked perfectly 🙂

Thanks again!

[amitchandak]

@Anonymous , Try a new column like

new column =
var _max = maxx(filter(Table, [cat] =earlier([cat]) && [Date] <earlier([Date])),[Date])
return
[value] - maxx(filter(Table, [cat] =earlier([cat]) && [Date] =_max),[value])

[Anonymous]

@amitchandakThank you very much for your reply!

Unfortunately I get an error ("syntax for return is incorrect").

Thanks again 🙂