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Value difference by Date and categorial variable

Hi all

 

I want to calculate the difference between values, based on the date as well as another categorial variable.

All that should be displayed in a waterfall diagram (column Expected Result). I attached a screenshot with dummy data and the expectet outcome.

 

Thanks in advance!

PBi Question.PNG

1 ACCEPTED SOLUTION
Microsoft
Microsoft

Hi @angryvoegi ,

 

Based on your description, you can do some steps as follows.

  1. Create a column to mark month.

 

Month = MONTH('Diff'[Date])

2.  Create a new measure.

 

Test Value =

var x1=MAXX(FILTER(ALL(Diff),[Month]=SELECTEDVALUE(Diff[Month])&&'Diff'[Cat]=SELECTEDVALUE(Diff[Cat])),'Diff'[Value])

var x2=MAXX(FILTER(ALL(Diff),[Month]=SELECTEDVALUE(Diff[Month])-1&&'Diff'[Cat]=SELECTEDVALUE(Diff[Cat])),'Diff'[Value])

return

x1-x2

 

Result:

v-yuaj-msft_0-1607301414935.png

 

Hope that's what you were looking for.

Best Regards,

Yuna

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

5 REPLIES 5
Super User III
Super User III

Hi,

Try this calculated column formula

=data[value]-lookupvalue(data[value],data[date],calculate(max(data[date]),filter(data,data[cat]=earlier(data[cat])&&data[date]<earlier(data[date]))),data[cat],data[cat])

Hope this helps.


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/
Microsoft
Microsoft

Hi @angryvoegi ,

 

Based on your description, you can do some steps as follows.

  1. Create a column to mark month.

 

Month = MONTH('Diff'[Date])

2.  Create a new measure.

 

Test Value =

var x1=MAXX(FILTER(ALL(Diff),[Month]=SELECTEDVALUE(Diff[Month])&&'Diff'[Cat]=SELECTEDVALUE(Diff[Cat])),'Diff'[Value])

var x2=MAXX(FILTER(ALL(Diff),[Month]=SELECTEDVALUE(Diff[Month])-1&&'Diff'[Cat]=SELECTEDVALUE(Diff[Cat])),'Diff'[Value])

return

x1-x2

 

Result:

v-yuaj-msft_0-1607301414935.png

 

Hope that's what you were looking for.

Best Regards,

Yuna

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

Hi, thank you very much for your help!! It worked perfectly 🙂

Thanks again!

Super User IV
Super User IV

@angryvoegi , Try a new column like

new column =
var _max = maxx(filter(Table, [cat] =earlier([cat]) && [Date] <earlier([Date])),[Date])
return
[value] - maxx(filter(Table, [cat] =earlier([cat]) && [Date] =_max),[value])



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Proud to be a Super User!

@amitchandakThank you very much for your reply!

Unfortunately I get an error ("syntax for return is incorrect").

Thanks again 🙂

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