Using MEDIAN as LOOKUP column?

[ericOnline]

Hello,

I want to LookUp records based on the record closest to the Median value of a column. 

Example:

MAP_ZOOM_LAT = 

VAR varMid = MEDIAN(table[column1])
RETURN

    LOOKUPVALUE(
        table[latitude], 
        varMid,
        BLANK()
    )

 The error I receive is:

"Function LOOKUPVALUE expects a column reference as argument number 2"

How do I determine which record is closest to the Median value in a given column?

Thank you

[v-jayw-msft]

Hi @ericOnline ,

Has the problem be solved? 

Best Regards,

Jay

[Greg_Deckler · Accepted solution]

@ericOnline Maybe this:

MAP_ZOOM_LAT = 
  VAR __varMid = MEDIAN(table[column1])
  VAR __Table = 
    ADDCOLUMNS(
      'table',
      "diff",ABS([latitude]-__varMid)
    )
  VAR __Min = MINX(__Table,[diff])
  VAR __Result = MINX(FILTER(__Table,[diff]=__Min),[ID])
RETURN
  [ID]

That's the general idea, basically a Lookup Min/Max - https://community.powerbi.com/t5/Quick-Measures-Gallery/Lookup-Min-Max/m-p/985814#M434

Not 100% of what you are trying to return/show so I just made up an "ID" column. You could use a variation of this as a flag variable that you could use as a Complex Selector - https://community.powerbi.com/t5/Quick-Measures-Gallery/The-Complex-Selector/m-p/1116633#M534

MAP_ZOOM_LAT = 
  VAR __CurrentLat = MAX(table[latitude])
  VAR __varMid = MEDIAN(table[column1])
  VAR __Table = 
    ADDCOLUMNS(
      'table',
      "diff",ABS([latitude]-__varMid)
    )
  VAR __Min = MINX(__Table,[diff])
  VAR __Result = IF(__CurrentLat = __Min, 1, 0)
RETURN
  __Result