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Hello All,
I have a summarization table that pulls from two different tables in my report. I would like to get the average from other columns split up by name.
For example I would like to populate the new column I created with the averages of M1 split up by Will. The values that I am gettting are the same for every name.
Any help is appreciated.
Solved! Go to Solution.
Hi @wcd1213 ,
According to your description, here's my solution. Create a calculated column.
Column =
AVERAGEX (
FILTER (
'Calculated Table',
'Calculated Table'[Name] = EARLIER ( 'Calculated Table'[Name] )
),
[M1]
)
Best Regards,
Community Support Team _ kalyj
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @wcd1213 ,
According to your description, here's my solution. Create a calculated column.
Column =
AVERAGEX (
FILTER (
'Calculated Table',
'Calculated Table'[Name] = EARLIER ( 'Calculated Table'[Name] )
),
[M1]
)
Best Regards,
Community Support Team _ kalyj
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @v-yanjiang-msft ,
Thank you for the reply.
I tested this expression and the column is not averaging by name. Is there something else I can add to the formula to acheive this?
Hi @wcd1213 ,
I create a sample and it averages by name as expected.
Do you have some difference with me?
I attach my sample below for your reference.
Best Regards,
Community Support Team _ kalyj
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @v-yanjiang-msft ,
I looked at your sample and i used the same expressions. However the table I am working on is summarized from two other tables.
Here is the expression I used to summarize the columns.
And here is my expression for getting the average.
Hi @wcd1213 ,
According to your snapshot, isn't 4.2857 the average of the name Will? If not, what the 4.2857 really is.
I recreate a sample like you, and it still get the correct result.
You can download my sample below to see the details.
Best Regards,
Community Support Team _ kalyj
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
4.2857 is the average of all of M1. I just realized my screenshot did not include the next name Joe. That average is the same:
I need the averages to be split between names.
Hi @wcd1213 ,
To veryfy the result, I calculate it manually.
For Will, sum is 90. The count of Will is 21, so the result of Will is correct(90/21=4.2857).
For Joe, sum is 60. The count of Will is 14, so the result of Will is correct(60/14=4.2857).
For Jim, the snapshot data is incomplete, so I can't calculate it manually.
As of now, the result is the same for each name is just a coincidence.
Best Regards,
Community Support Team _ kalyj
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