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motzplo
Regular Visitor

Timediff between rows depending on index

Hello all,

 

I have the following problem and I hope some of you can help me. I would like to calculate the time difference between two rows, depending on the ID. Time difference between two rows of a different ID is not possible. The time difference should look like the following picture.

PowerBi.JPG

 

 

Thank you in advance.

 

1 ACCEPTED SOLUTION
v-jiascu-msft
Employee
Employee

Hi @motzplo,

 

Try this formula, please.

Column =
VAR currentID = [ID]
VAR currentIndex = [Index]
VAR nextDatetime =
    CALCULATE (
        MIN ( Table1[Datetime] ),
        FILTER (
            'Table1',
            'Table1'[ID] = currentID
                && 'Table1'[Index]
                = currentIndex + 1
        )
    )
RETURN
    DATEDIFF ( [Datetime], nextDatetime, MINUTE )

Timediff_between_rows_depending_on_index

 

Best Regards,

Dale

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
Ashish_Mathur
Super User
Super User

Hi,

 

Try this calculated column formula

 

=CALCULATE(MIN(Data[Datetime]),FILTER(Data,Data[ID]=EARLIER(Data[ID])&&Data[Datetime]>EARLIER(Data[Datetime])))-[Datetime]

 

Hope this helps.


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/
v-jiascu-msft
Employee
Employee

Hi @motzplo,

 

Try this formula, please.

Column =
VAR currentID = [ID]
VAR currentIndex = [Index]
VAR nextDatetime =
    CALCULATE (
        MIN ( Table1[Datetime] ),
        FILTER (
            'Table1',
            'Table1'[ID] = currentID
                && 'Table1'[Index]
                = currentIndex + 1
        )
    )
RETURN
    DATEDIFF ( [Datetime], nextDatetime, MINUTE )

Timediff_between_rows_depending_on_index

 

Best Regards,

Dale

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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