Sumar.si entre dos columnas

[JDU]

Estimados, necesito por favor vuestra ayuda para encontrar alguna fórmula que me permita sumar datos de una columna pero según los criterios de otra. La condición es que sume solo si encuentra que el dato es único en la columna criterio.

Dato 1	Criterio
10	45001201
10	45001201
20	45001202
30	45001203
40	45001204
100

Debe sumar solo una vez los datos de las primeras dos filas dado que en la columna criterio se repite un valor dos veces, por tanto debe considerar una sola vez.

Espero haberlo explicado bien y que me puedan ayudar.

Gracias!

[v-lionel-msft]

Hi @JDU ,

Maybe you can try this:

Column = 
VAR x = 
CALCULATE(
    COUNT([Criterio]),
    ALLEXCEPT(
        table,
        [Dato 1]
    )
)
RETURN
IF(
    x = 1,
    ADDCOLUMNS( )

)

Best regards,
Lionel Chen

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[JDU]

An error appears with the expression "ADDCOLUMNS".
Please don't forget that what I need is to add up the data in the "Dato 1" column if the values in the "Criterio" column are different.

Anyway, thank you very much for your help!

[az38]

Hi @JDU 

try to create a new table 

Table2 = DISTINCT('Table')

It will remove duplicates

do not hesitate to give a kudo to useful posts and mark solutions as solution

[JDU]

but, how do I relate the data from the new table to the table I need to add?

[az38]

@JDU 

just use in visual a new table instead of old with repeated values

do not hesitate to give a kudo to useful posts and mark solutions as solution

[JDU]

What I need to do is add up the values in one column if the values in another column are unique. When I create a new table with unique values I can't relate it to the original table.

I probably don't know how to do it.

[PaulDBrown · Accepted solution]

@JDU 

Try this:

1) Calculate the average of your "Criterio":

Average = AVERAGE(Criterio[Dato 1])

2) Use SUMX with DISTINCT to sum these average values

Suma sin duplicados = SUMX(DISTINCT(Criterio[Criterio]); [Average])

To get this result:

[JDU]

The solution looks good, it's just what I need but I can't execute it. Consultations:

1) The average I create as a new column ... I do not get the same results as you.
2) SUMX I use it as a new measure?

Thanks for your help!

[PaulDBrown]

@JDU 

They are 2 seperate measures (no new columns)..