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Hi All,
I have this table :
ID | StartDate | EndDate | Price | CountofNum |
123 | 1/1/21 | 1/31/21 | 9999 | |
123 | 2/1/21 | 2/28/21 | 10 | 1 |
123 | 3/1/21 | 3/31/21 | 10 | 0 |
123 | 4/1/21 | 4/30/21 | 10 | 0 |
123 | 5/1/21 | 5/16/21 | 9999 | |
12345 | 1/1/21 | 1/31/21 | 9999 | |
12345 | 2/1/21 | 2/28/21 | 9999 | |
12345 | 3/1/21 | 3/31/21 | 20 | 1 |
12345 | 4/1/21 | 4/30/21 | 20 | 0 |
12345 | 5/1/21 | 5/31/21 | 20 | 0 |
12345 | 6/1/21 | 6/30/21 | 20 | 0 |
123456789 | 1/1/21 | 1/31/21 | 1 | |
123456789 | 2/1/21 | 2/14/21 | 9999 |
I'm looking for dax that shows me the average of all rows that the value in the Table[CountofNum] column is '1' or '0' per ID.
For example:
ID | SumOfData |
123 | 1 + 0 + 0 = 3 |
12345 | 1 + 0 + 0 + 0 = 4 |
123456789 | 1 = 1 |
and then, Table[SumOfData] / Table[ID]
(3 + 4 + 1) / 3
'3' is beacuse the ID unique.
thanks!
Solved! Go to Solution.
Try This
averageid=
var nbid = calculate(DISTINCTCOUNT(Feuil10[ID]),Feuil10[ CountofNum] in {0,1})
Hi, @dolevh
Referring to @Anonymous ‘s solution, I made a sample for reference.
If your problem has been solved, please accept a helpful reply as solution to close this thread, so that other community members will easily find the solution when they get the same issue.
Best Regards,
Community Support Team _ Eason
Try This
averageid=
var nbid = calculate(DISTINCTCOUNT(Feuil10[ID]),Feuil10[ CountofNum] in {0,1})
@dolevh You can use AVERAGEX and FILTER
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