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dolevh
Helper II
Helper II

Sum of rows per ID and then Avg of All

Hi All, 

 

I have this table : 

 

ID  StartDate  EndDate  Price  CountofNum
123  1/1/21  1/31/21   9999
123  2/1/21  2/28/21  10  1
123  3/1/21  3/31/21  10  0
123  4/1/21  4/30/21  10  0
123  5/1/21  5/16/21   9999
12345  1/1/21  1/31/21   9999
12345  2/1/21  2/28/21   9999
12345  3/1/21  3/31/21  20  1
12345  4/1/21  4/30/21  20  0
12345  5/1/21  5/31/21  20  0
12345  6/1/21  6/30/21  20  0
123456789  1/1/21  1/31/21   1
123456789  2/1/21  2/14/21   9999

 

I'm looking for dax that shows me the average of all rows that the value in the Table[CountofNum] column is '1' or '0' per ID.

 

For example: 

ID   SumOfData
123   1 + 0 + 0 = 3
12345   1 + 0 + 0 + 0 = 4
123456789   1 = 1

 

and then, Table[SumOfData] / Table[ID]
(3 + 4 + 1) / 3 
'3' is beacuse the ID unique.

 

thanks!

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Try This

averageid=

var nbid = calculate(DISTINCTCOUNT(Feuil10[ID]),Feuil10[  CountofNum] in {0,1})

var nb01 = calculate(COUNT(Feuil10[  CountofNum]),Feuil10[  CountofNum] in {0,1})
var result= 
divide([nb01],[nbid],0)
 
return 
result
 

View solution in original post

3 REPLIES 3
v-easonf-msft
Community Support
Community Support

Hi, @dolevh 

Referring to @Anonymous ‘s solution, I made a sample for reference.

veasonfmsft_0-1653468527116.png

 

If your problem has been solved, please accept a helpful reply as solution to close this thread, so that other community members will easily find the solution when they get the same issue.

 

Best Regards,
Community Support Team _ Eason

Anonymous
Not applicable

Try This

averageid=

var nbid = calculate(DISTINCTCOUNT(Feuil10[ID]),Feuil10[  CountofNum] in {0,1})

var nb01 = calculate(COUNT(Feuil10[  CountofNum]),Feuil10[  CountofNum] in {0,1})
var result= 
divide([nb01],[nbid],0)
 
return 
result
 
Greg_Deckler
Super User
Super User

@dolevh You can use AVERAGEX and FILTER


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