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Frequent Visitor

## Sum of Distinct Count by column

Hello Everyone,

I am having trouble calculating sum of Distinct Count. Basically, I would like to calculate Distinct count regarding a different column. Here is the example:

Term                ID

Spring 15          1

Spring 15          2

Spring 15          1

Spring 16          1

Spring 16          1

Spring 16          3

Spring 17          4

Spring 17          1

My original formula is DISTINCTCOUNT(Table[ID]). But it gives a total number 4. However, I would like to calculate sum of distinct ID for every term. It should have,

-2 distinct count for Spring 15,

-2 distinct count for Spring 16

-2 distinct count for Spring 17.

So distinct count would be 6 instead of 4.

By the way, there is something to point out. I was eligible to get correct number with a complicated formula but my page should react when we filter with a slicer. When I have something like (="Spring 15"), it does not response when Spring 15 is unselected in slicer.

It is not as complicated as it is seen. To recap, distinct count should be calculated for every data in column "term".

Sorry for the long message. I hope I can solve my issue.

1 ACCEPTED SOLUTION
Super User IV

You could create a new column that concatenates Term and ID and then create a measure that does a DISTINCTCOUNT of that column. This measure should react appropriately to slicers and such. So:

Column

`TermIDs =CONCATENATE([Term],[ID])`

Measure

`DistinctTermIDs = DISTINCTCOUNT([TermIDs])`

---------------------------------------

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7 REPLIES 7
New Member

I have a set of ids

1

2

3

1

1

2

4

5

5

and i want the id and its count

1 - 3 times

2 - 2 times

3 - 1 time

4 - 1 time

5 - 2 times

and i have written a measure for the same

Measure = CONCATENATE(DISTINCT(Activityx[Column1.AppId]), DISTINCTCOUNT(Activityx[Column1.AppId]))

but i am unable to get the expected result. How can i achive that?

New Member

I have a set of ids

1

2

3

1

1

2

4

5

5

and i want the id and its count

1 - 3 times

2 - 2 times

3 - 1 time

4 - 1 time

5 - 2 times

and i have written a measure for the same

Measure = CONCATENATE(DISTINCT(Activityx[Column1.AppId]), DISTINCTCOUNT(Activityx[Column1.AppId]))

but i am unable to get the expected result. How can i achive that?

Super User IV

You could create a new column that concatenates Term and ID and then create a measure that does a DISTINCTCOUNT of that column. This measure should react appropriately to slicers and such. So:

Column

`TermIDs =CONCATENATE([Term],[ID])`

Measure

`DistinctTermIDs = DISTINCTCOUNT([TermIDs])`

---------------------------------------

@ me in replies or I'll lose your thread!!!

##### I have a NEW book! DAX Cookbook from Packt
Over 120 DAX Recipes!

Did I answer your question? Mark my post as a solution!

Proud to be a Super User!

Frequent Visitor

Hello,

I would like to ask question as a continue of your answer, when we calculate a measure

`DistinctTermIDs = DISTINCTCOUNT([TermIDs])`

How to put this measure result in new column for every product (row).

Example, we have as a product name

Spring15

Spring15

Spring16

And create DISTINCTCOUNT measure that we can manually filter and for Spring 15 Total will return 2.

How to put this value 2 in the same table, near each item?

Result should be

ProductName   No. (from measure)

Spring15           2

Spring15           2

Spring16           1

Thank you in advance

Frequent Visitor

Thanks , this helped me.

Regular Visitor

So how would you filter out a distict value?

So in the example above how would you say return the distinct values = SPRING15

Frequent Visitor

I am surprised how fast you replied.

Thank you so much!

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