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Good afternoon,
I have some problems to get the next filter whith a slice.
I have a table like this one:
PersonalID | Tecnology |
1 | Java |
1 | Spark |
1 | MongoDB |
2 | Java |
2 | SQL |
My question is, how can I do for when I put two or more tecnologies in the slice, for example Java and Spark, only appears in the table, the person whith id 1, but no the person 2?
I want to get a "and" whith the slicer and no a "or".
Thank you for your help
Solved! Go to Solution.
Hi, @fortiz98
According to your description, I think you can create a dictinct table and use it as a slicer, then add a measure in filter pane to filter your desired result.
Like this:
Table 2 = DISTINCT('Table'[Tecnology])
Measure =
VAR a =
CALCULATETABLE (
DISTINCT ( 'Table'[Tecnology] ),
FILTER ( ALL ( 'Table' ), [PersonalID] = SELECTEDVALUE ( 'Table'[PersonalID] ) )
)
RETURN
IF (
(
COUNTROWS ( DISTINCT ( 'Table 2'[Tecnology] ) )
= COUNTROWS ( FILTER ( DISTINCT ( 'Table 2'[Tecnology] ), [Tecnology] IN a ) )
&& SELECTEDVALUE ( 'Table'[Tecnology] ) IN DISTINCT ( 'Table 2'[Tecnology] )
)
|| NOT ( ISFILTERED ( 'Table 2'[Tecnology] ) ),
1,
0
)
Here is my sample .pbix file.Hope it helps.
If it doesn’t solve your problem, please feel free to ask me.
Best Regards
Janey Guo
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi, @fortiz98
According to your description, I think you can create a dictinct table and use it as a slicer, then add a measure in filter pane to filter your desired result.
Like this:
Table 2 = DISTINCT('Table'[Tecnology])
Measure =
VAR a =
CALCULATETABLE (
DISTINCT ( 'Table'[Tecnology] ),
FILTER ( ALL ( 'Table' ), [PersonalID] = SELECTEDVALUE ( 'Table'[PersonalID] ) )
)
RETURN
IF (
(
COUNTROWS ( DISTINCT ( 'Table 2'[Tecnology] ) )
= COUNTROWS ( FILTER ( DISTINCT ( 'Table 2'[Tecnology] ), [Tecnology] IN a ) )
&& SELECTEDVALUE ( 'Table'[Tecnology] ) IN DISTINCT ( 'Table 2'[Tecnology] )
)
|| NOT ( ISFILTERED ( 'Table 2'[Tecnology] ) ),
1,
0
)
Here is my sample .pbix file.Hope it helps.
If it doesn’t solve your problem, please feel free to ask me.
Best Regards
Janey Guo
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
@fortiz98 here is a great article on this.
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