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Anonymous
Not applicable

Shared time axis on 2 different dates

Hi,

 

Here is a sample :

ticket_numbercreation dateclosure date
ticket 102/01/201902/01/2019
ticket 205/01/201906/01/2019
ticket 310/01/201911/01/2019
ticket 415/01/201917/02/2019
ticket 520/02/2019

 

 

I would like to have this :

Monthcreatedclosedbacklog
2019-01431
2019-02111

 

How can do to share the same time axis and calculate the rolling difference, please ?

 

Thanks,

Romain

1 ACCEPTED SOLUTION
v-yuta-msft
Community Support
Community Support

@Anonymous ,

 

You can create calculate column using DAX like pattern below:

Created = CALCULATE(COUNT(Table1[ticket_number]), FILTER(Table1, MONTH(Table1[creation date]) = MONTH(EARLIER(Table1[creation date]))))

Closed = CALCULATE(COUNT(Table1[ticket_number]), FILTER(Table1, MONTH(Table1[closure date]) = MONTH(EARLIER(Table1[closure date]))))

Capture.PNG  

 

Community Support Team _ Jimmy Tao

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

3 REPLIES 3
v-yuta-msft
Community Support
Community Support

@Anonymous ,

 

You can create calculate column using DAX like pattern below:

Created = CALCULATE(COUNT(Table1[ticket_number]), FILTER(Table1, MONTH(Table1[creation date]) = MONTH(EARLIER(Table1[creation date]))))

Closed = CALCULATE(COUNT(Table1[ticket_number]), FILTER(Table1, MONTH(Table1[closure date]) = MONTH(EARLIER(Table1[closure date]))))

Capture.PNG  

 

Community Support Team _ Jimmy Tao

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Anonymous
Not applicable

Thanks @v-yuta-msft , that works for Created and Closed, do you have an idea how to calculate the rolling difference, please ?

Thanks

@Anonymous ,

 

Could share more details/logic about "Rolling Difference" you mentioned?

 

Community Support Team _ Jimmy Tao

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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