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Kudy
Frequent Visitor

Sameperiodlastyear per category

My first post ever 🙂

Hi,
I have the following table called Transactions from an online shop:

Order ID    Item ID  Category  Date
444 applefruit1-jan-2021
555  pearfruit2-jan-2021
666 applefruit3-jan-2021
777  potatovegetable4-jan-2021
111  orangefruit1-jan-2020
222  broccolivegetable2-jan-2020
333cabbagevegetable3-jan-2020


Now I have created a slicer for Date and a matrix table.
In my matrix table, I have now two first columns below (A&B).
What I don't have is column C, which counts LY values for the date range I chose through my slicer. 

A  
Row: Category  
  B
 Values: Count Item ID  
  C
  Values: Count Item ID      (sameperiodlastyear)
Fruit31
Vegetable12


Really appreciate your help!

Br,
Kudy

1 ACCEPTED SOLUTION
v-stephen-msft
Community Support
Community Support

Hi @Kudy ,

 

You could create a seperate year table.

Table 2 = DISTINCT('Table'[Date].[Year])

1.png

 

Two measure are created as

Count Item ID = IF(ISFILTERED('Table 2'[Year]),CALCULATE(COUNT('Table'[Item ID]),FILTER('Table',YEAR([Date])=SELECTEDVALUE('Table 2'[Year]))),COUNT('Table'[Item ID]))
Count Item ID(sameperiodlastyear) = IF(ISFILTERED('Table 2'[Year]), CALCULATE(COUNT('Table'[Item ID]),FILTER('Table',YEAR([Date])=SELECTEDVALUE('Table 2'[Year])-1)),COUNT('Table'[Item ID]))

2.png

 

 

Best Regards,

Stephen Tao

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

View solution in original post

2 REPLIES 2
v-stephen-msft
Community Support
Community Support

Hi @Kudy ,

 

You could create a seperate year table.

Table 2 = DISTINCT('Table'[Date].[Year])

1.png

 

Two measure are created as

Count Item ID = IF(ISFILTERED('Table 2'[Year]),CALCULATE(COUNT('Table'[Item ID]),FILTER('Table',YEAR([Date])=SELECTEDVALUE('Table 2'[Year]))),COUNT('Table'[Item ID]))
Count Item ID(sameperiodlastyear) = IF(ISFILTERED('Table 2'[Year]), CALCULATE(COUNT('Table'[Item ID]),FILTER('Table',YEAR([Date])=SELECTEDVALUE('Table 2'[Year])-1)),COUNT('Table'[Item ID]))

2.png

 

 

Best Regards,

Stephen Tao

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

View solution in original post

Greg_Deckler
Super User
Super User

@Kudy There are two main ways of doing this, using TI functions like SAMEPERIODLASTYEAR or not:

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