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jvangrunderbeec
Frequent Visitor

Running total over years

I have a running total over all the year, but i also need a running total that starts counting every year.
running total.PNG

Now as you can see in the picture it starts in 2012 but then continues in 2013 with the data from dec 2012. I need another measure that starts from january every year.

 

My code so far is:
Cumulative Sales (over years)=
IF (
COUNTROWS ( Fact_Transactielijnen ) > 0;
CALCULATE(
[Bedrag];
FILTER(
ALL (Dim_Date[Date]);
Dim_Date[Date] <= MAX ((Dim_Date[Date]))
)
);
BLANK ()
)

 

 

Thanks in advance

1 ACCEPTED SOLUTION
v-shex-msft
Community Support
Community Support

Hi @jvangrunderbeec,

 

You can add condition to check current year to break cumulative calculate across different years:

 

Cumulative Sales (over years) =
VAR CurrDate =
    MAX ( Dim_Date[Date] )
RETURN
    IF (
        COUNTROWS ( Fact_Transactielijnen ) > 0;
        CALCULATE (
            [Bedrag];
            FILTER (
                ALLSELECTED ( Dim_Date );
                Dim_Date[Date] <= CurrDate
                    && YEAR ( Dim_Date[Date] ) = YEAR ( CurrDate )
            )
        );
        BLANK ()
    )

 

Regards,

Xiaoxin Sheng

Community Support Team _ Xiaoxin
If this post helps, please consider accept as solution to help other members find it more quickly.

View solution in original post

1 REPLY 1
v-shex-msft
Community Support
Community Support

Hi @jvangrunderbeec,

 

You can add condition to check current year to break cumulative calculate across different years:

 

Cumulative Sales (over years) =
VAR CurrDate =
    MAX ( Dim_Date[Date] )
RETURN
    IF (
        COUNTROWS ( Fact_Transactielijnen ) > 0;
        CALCULATE (
            [Bedrag];
            FILTER (
                ALLSELECTED ( Dim_Date );
                Dim_Date[Date] <= CurrDate
                    && YEAR ( Dim_Date[Date] ) = YEAR ( CurrDate )
            )
        );
        BLANK ()
    )

 

Regards,

Xiaoxin Sheng

Community Support Team _ Xiaoxin
If this post helps, please consider accept as solution to help other members find it more quickly.

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