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Frequent Visitor

## Return the 2nd Tuesday of every Month

I am trying to return the 2nd Tuesday of every month. My table has a date for everyday. How can I return this based on the that field.

1 ACCEPTED SOLUTION

Accepted Solutions
Super Contributor

## Re: Return the 2nd Tuesday of every Month

Please try this as a caluculated column

```Is 2nd Tuesday =
VAR a = 'Dates'[Date]
VAR y = FILTER(
ALL(Dates[Date]),
YEAR('Dates'[Date]) = YEAR(a) &&
MONTH('Dates'[Date]) = MONTH(a) &&
DAY([Date]) > 7 &&
DAY([Date]) < 15 &&
WEEKDAY([Date],3) = 1)
RETURN MAXX(y,[Date])```

Proud to be a Datanaut!

14 REPLIES 14
Super User

## Re: Return the 2nd Tuesday of every Month

Hi @tacobannas,

Create these two column:

```MonthWeekday = MONTH('Calendar'[Date]) & WEEKDAY('Calendar'[Date])

weekday_Number = WEEKDAY('Calendar'[Date])```

Then create this measure:

```2nd Tuesday =
VAR Date_Max =
MAX ( 'Calendar'[Date] )
VAR Month_week_Max =
MAX ( 'Calendar'[MonthWeekday] )
RETURN
IF (
CALCULATE (
COUNT ( 'Calendar'[MonthWeekday] ),
'Calendar'[Date] <= Date_Max,
'Calendar'[MonthWeekday] = Month_week_Max
)
= 2
&& MAX ( 'Calendar'[weekday_Number] ) = 3,
"2nd",
""
)```

Add the measure as a filter on your visuals and you should get the result you need:

Regards,

MFelix

Proud to be a Datanaut!

Frequent Visitor

## Re: Return the 2nd Tuesday of every Month

Thanks, that works as a measure, but I was hoping to return the 2nd Tuesday each month as a date in a column. So for everday of the month in my calendar table I would have a corresponding column with the 2nd Tuesday date.

Super Contributor

## Re: Return the 2nd Tuesday of every Month

Please try this as a calculated column

```Is 2nd Tuesday =
VAR x =  IF(WEEKDAY([Date],1) = 3 , DAY([Date]) , 0)
RETURN IF(x > 7 && x < 15 , 1 , 0)```

Proud to be a Datanaut!

Frequent Visitor

## Re: Return the 2nd Tuesday of every Month

That appears to work returning true or false, however I want to return the actual date of the 2nd Tuesday.

Super Contributor

## Re: Return the 2nd Tuesday of every Month

Hi

```Is 2nd Tuesday =
VAR x =  IF(WEEKDAY([Date],1) = 3 , DAY([Date]) , 0)
RETURN IF(x > 7 && x < 15 , [Date] , blank())```

Proud to be a Datanaut!

Highlighted
Super Contributor

## Re: Return the 2nd Tuesday of every Month

A power Query solution: add a column with formula:

`= Date.StartOfWeek(#date(Date.Year([Date]),Date.Month([Date]),14),Day.Tuesday)`

This wil take the 14th of the year/month of the date, and from that date: the start of the week, with Tuesday as the first day of the week. So that must be the 2nd Tuesday in the month.

Specializing in Power Query Formula Language (M)
Frequent Visitor

## Re: Return the 2nd Tuesday of every Month

This appears to be working, but I need that to be filled into every row value pair, not blank in the instance it is not the 2nd Tuesday.

Super Contributor

## Re: Return the 2nd Tuesday of every Month

So do you mean every row for the month will carry the date that happens to be the 2nd tuesday of each month?

Proud to be a Datanaut!

Super Contributor

## Re: Return the 2nd Tuesday of every Month

Please try this as a caluculated column

```Is 2nd Tuesday =
VAR a = 'Dates'[Date]
VAR y = FILTER(
ALL(Dates[Date]),
YEAR('Dates'[Date]) = YEAR(a) &&
MONTH('Dates'[Date]) = MONTH(a) &&
DAY([Date]) > 7 &&
DAY([Date]) < 15 &&
WEEKDAY([Date],3) = 1)
RETURN MAXX(y,[Date])```

Proud to be a Datanaut!

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