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oren
Helper III
Helper III

Ranking by groups

Hi

 

i what to create a Mesure that rankink rows for groups of values order by number -

same as in sql row_number over (partition by X,Y,Z order by L)

 

is it possible?

 

tharank.JPGnk you very mutch

 

oren 

1 ACCEPTED SOLUTION
themistoklis
Community Champion
Community Champion

@oren

 

Please ignore the previous formula.

This one works:

 

Sorting_Rank = 
	RANKX (
        FILTER(
			ALL(
				'Table'[A], 'Table'[B], 'Table'[C]
				),
            'Table'[A] = MAX('Table'[A]) &&
            'Table'[B] = MAX('Table'[B])
            ),
			CALCULATE(SUM('Table'[C])), , ASC, Dense
			)

View solution in original post

6 REPLIES 6
themistoklis
Community Champion
Community Champion

@oren

 

Please ignore the previous formula.

This one works:

 

Sorting_Rank = 
	RANKX (
        FILTER(
			ALL(
				'Table'[A], 'Table'[B], 'Table'[C]
				),
            'Table'[A] = MAX('Table'[A]) &&
            'Table'[B] = MAX('Table'[B])
            ),
			CALCULATE(SUM('Table'[C])), , ASC, Dense
			)
themistoklis
Community Champion
Community Champion

@oren

 

Try the following formula:

 

Sorting Rank = IF (
    HASONEVALUE ( 'Table'[A]), 
    RANKX ( ALL ( 'Table'[A], 'Table'[B] ), SUM('Table'[C]), , ASC, Dense)
)
v-chuncz-msft
Community Support
Community Support

@oren,

 

You may also try ISONORAFTER.

Community Support Team _ Sam Zha
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Never used ISONORAFTER before but will definately check. Thanks for Suggestion.

AnkitBI
Solution Sage
Solution Sage

Please try like below.

 

Measure 11 = RANKX(FILTER(all(Table1),Table1[Column1] = max(Table1[Column1]) && Table1[Column2] = max(Table1[Column2])),CALCULATE(sum(Table1[Column3])),,ASC,Skip)

Regards
AJ
Do Like Post if response seems good and Worth liking.
Do Mark as Solution if response resolved your Issue.

it dosent work- i am getting only "1" ( but maybe i am doing somthing not right)

 

thanks

 

 

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