RANKX on a DISTINCTCOUNT ?

[Anonymous]

Hello everyone,

am I the only one getting mad with the RANKX function ? each time I have to use it, I struggle so hard :((

I've seen many posts on the Internet but I can't figure it out.

what I want is simple, a rank of the clients by the number of projects. (housing building projects....clients names substituted by bands names :))

I always have '1'

#HOW_MANY_PROJECTS = DISTINCTCOUNT(Table2[ID_PROJECT])

#HOW_MANY_FLATS = SUMX(
SUMMARIZE(Table2;Table2[ID_PROJECT];Table2[HOW_MANY_FLATS]);Table2[HOW_MANY_FLATS])

I've tried different combination of formulas for RANKX

RANK = RANKX(Table2;
    CALCULATE([#HOW_MANY_PROJECTS]);;DESC;Dense)

how to get a proper rank please ?

many thanks !

[Zubair_Muhammad · Accepted solution]

@Anonymous 

Try Following

RANK =
RANKX ( ALLSELECTED ( TableName[Client] ), [#HOW_MANY_PROJECTS],, DESC, DENSE )

[Anonymous]

Thank you @Zubair_Muhammad !