Hi everyone, I'm having a problem that should be very simple to solve but I've looked everywhere and couldn't find an answer.
I have a table, like the image below:
In this table I have a name of an individual [name], a date [date] and a running value of this persons total xp [xp].
What I've been strugling is to find the value for each person of each single day. For example, for the character Ulvis, the xp today should be (Ulvis [xp] today) - (Ulvis [xp] yesterday) and so on.
I managed to create a column where it sort of works, but not completely, because the xp can increase and also decrease, and this formula doesn't work if the xp decreases from one day to the other:
Here is my result:
name | vocation | level | xp | date | Índice | XP Diaria |
Best Kina | Elder Druid | 435 | 1.358.049.628 | 21/01/2023 | 671 | 1.358.049.628 |
Best Kina | Elder Druid | 435 | 1.353.809.182 | 22/01/2023 | 1621 | -4.240.446 |
Best Kina | Elder Druid | 435 | 1.353.809.182 | 23/01/2023 | 2571 | -4.240.446 |
Best Kina | Elder Druid | 435 | 1.354.952.480 | 24/01/2023 | 3524 | -3.097.148 |
Best Kina | Elder Druid | 434 | 1.349.341.097 | 25/01/2023 | 4477 | -8.708.531 |
Best Kina | Elder Druid | 435 | 1.356.881.477 | 26/01/2023 | 5423 | -1.168.151 |
Best Kina | Elder Druid | 436 | 1.366.596.988 | 27/01/2023 | 6369 | 8.547.360 |
Best Kina | Elder Druid | 436 | 1.366.596.988 | 28/01/2023 | 7322 | 0 |
Ulvis | Elder Druid | 542 | 2.629.227.131 | 21/01/2023 | 413 | 2.629.227.131 |
Ulvis | Elder Druid | 543 | 2.639.848.792 | 22/01/2023 | 1364 | 10.621.661 |
Ulvis | Elder Druid | 544 | 2.656.424.542 | 23/01/2023 | 2310 | 16.575.750 |
Ulvis | Elder Druid | 545 | 2.670.269.464 | 24/01/2023 | 3261 | 13.844.922 |
Ulvis | Elder Druid | 546 | 2.684.681.945 | 25/01/2023 | 4209 | 14.412.481 |
Ulvis | Elder Druid | 547 | 2.702.924.968 | 26/01/2023 | 5154 | 18.243.023 |
Ulvis | Elder Druid | 548 | 2.718.618.346 | 27/01/2023 | 6105 | 15.693.378 |
Ulvis | Elder Druid | 549 | 2.734.267.729 | 28/01/2023 | 7053 | 15.649.383 |
And here is the expected result:
name | vocation | level | xp | date | Índice | XP Diaria |
Best Kina | Elder Druid | 435 | 1.358.049.628 | 21/01/2023 | 671 | 1.358.049.628 |
Best Kina | Elder Druid | 435 | 1.353.809.182 | 22/01/2023 | 1621 | -4.240.446 |
Best Kina | Elder Druid | 435 | 1.353.809.182 | 23/01/2023 | 2571 | 0 |
Best Kina | Elder Druid | 435 | 1.354.952.480 | 24/01/2023 | 3524 | 1.143.298 |
Best Kina | Elder Druid | 434 | 1.349.341.097 | 25/01/2023 | 4477 | -5.611.383 |
Best Kina | Elder Druid | 435 | 1.356.881.477 | 26/01/2023 | 5423 | 7.540.380 |
Best Kina | Elder Druid | 436 | 1.366.596.988 | 27/01/2023 | 6369 | 9.715.511 |
Best Kina | Elder Druid | 436 | 1.366.596.988 | 28/01/2023 | 7322 | 0 |
Ulvis | Elder Druid | 542 | 2.629.227.131 | 21/01/2023 | 413 | 2.629.227.131 |
Ulvis | Elder Druid | 543 | 2.639.848.792 | 22/01/2023 | 1364 | 10.621.661 |
Ulvis | Elder Druid | 544 | 2.656.424.542 | 23/01/2023 | 2310 | 16.575.750 |
Ulvis | Elder Druid | 545 | 2.670.269.464 | 24/01/2023 | 3261 | 13.844.922 |
Ulvis | Elder Druid | 546 | 2.684.681.945 | 25/01/2023 | 4209 | 14.412.481 |
Ulvis | Elder Druid | 547 | 2.702.924.968 | 26/01/2023 | 5154 | 18.243.023 |
Ulvis | Elder Druid | 548 | 2.718.618.346 | 27/01/2023 | 6105 | 15.693.378 |
Ulvis | Elder Druid | 549 | 2.734.267.729 | 28/01/2023 | 7053 | 15.649.383 |
Thanks in advance!
Best regards!
Solved! Go to Solution.
Hi @Mugizib ,
Please try:
Column =
var _index = MAXX(FILTER('XP por dia',[name]=EARLIER('XP por dia'[name])&&[Índice]<EARLIER('XP por dia'[Índice])),[Índice])
VAR _maxvalue =
CALCULATE (
MAX ( 'XP por dia'[xp] ),
FILTER (
'XP por dia',
'XP por dia'[name] = EARLIER ( 'XP por dia'[name] )
&& 'XP por dia'[Índice] = _index
)
)
RETURN
[xp]-_maxvalue
Final output:
Best Regards,
Jianbo Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @Mugizib ,
Please try:
Column =
var _index = MAXX(FILTER('XP por dia',[name]=EARLIER('XP por dia'[name])&&[Índice]<EARLIER('XP por dia'[Índice])),[Índice])
VAR _maxvalue =
CALCULATE (
MAX ( 'XP por dia'[xp] ),
FILTER (
'XP por dia',
'XP por dia'[name] = EARLIER ( 'XP por dia'[name] )
&& 'XP por dia'[Índice] = _index
)
)
RETURN
[xp]-_maxvalue
Final output:
Best Regards,
Jianbo Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
@Mugizib Mean Time Between Failure (MTBF) - Microsoft Power BI Community
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