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hazaboy9
Frequent Visitor

Power Query - List.Min for one column based on duplicate values in another column

Hi Everyone,

 

Having some problems where I have row level data with duplicates values that I need to find a minimum value for.  In the below screenshot i would like to see a 3rd column that shows the minimum date difference for each "Ctr & Visit Code" value.

 

Is there a calculation in Power Query that i can use 

 

hazaboy9_0-1599108795709.png

 

2 ACCEPTED SOLUTIONS
mhossain
Solution Sage
Solution Sage

@hazaboy9 

 

Try below code in your advance editor/powerquery, it should work.

 

let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMjRQ0lEyVIrVATKN4ExLOMsCIQ1SaQRhGsKZxghREygzFgA=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [#"Date Difference" = _t, #"Ctr & Visit Code" = _t]),
#"Changed Type" = Table.TransformColumnTypes(Source,{{"Date Difference", Int64.Type}, {"Ctr & Visit Code", Int64.Type}}),
#"Grouped Rows" = Table.Group(#"Changed Type", {"Ctr & Visit Code"}, {{"Count", each _, type table [Date Difference=nullable number, #"Ctr & Visit Code"=nullable number]}}),
#"Added Custom1" = Table.AddColumn(#"Grouped Rows", "Custom.1", each List.First(List.Sort(Table.Column([Count],"Date Difference")))),
#"Expanded Count" = Table.ExpandTableColumn(#"Added Custom1", "Count", {"Date Difference"}, {"Count.Date Difference"})
in
#"Expanded Count"

 

Let me know if above makes sense

View solution in original post

Icey
Community Support
Community Support

Hi @hazaboy9 ,

 

Try to use "Group" by the "Ctr & Visit Code" column and return a column of min value of "Date Difference" column.

 

 

Best Regards,

Icey

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

3 REPLIES 3
Icey
Community Support
Community Support

Hi @hazaboy9 ,

 

Try to use "Group" by the "Ctr & Visit Code" column and return a column of min value of "Date Difference" column.

 

 

Best Regards,

Icey

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

mhossain
Solution Sage
Solution Sage

@hazaboy9 

 

Try below code in your advance editor/powerquery, it should work.

 

let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMjRQ0lEyVIrVATKN4ExLOMsCIQ1SaQRhGsKZxghREygzFgA=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [#"Date Difference" = _t, #"Ctr & Visit Code" = _t]),
#"Changed Type" = Table.TransformColumnTypes(Source,{{"Date Difference", Int64.Type}, {"Ctr & Visit Code", Int64.Type}}),
#"Grouped Rows" = Table.Group(#"Changed Type", {"Ctr & Visit Code"}, {{"Count", each _, type table [Date Difference=nullable number, #"Ctr & Visit Code"=nullable number]}}),
#"Added Custom1" = Table.AddColumn(#"Grouped Rows", "Custom.1", each List.First(List.Sort(Table.Column([Count],"Date Difference")))),
#"Expanded Count" = Table.ExpandTableColumn(#"Added Custom1", "Count", {"Date Difference"}, {"Count.Date Difference"})
in
#"Expanded Count"

 

Let me know if above makes sense

amitchandak
Super User
Super User

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