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Hello, everyone!
I have a problem which I believe is very easy to solve; however, ...I haven't been able to so, I'm asking for your help.
Below, I have a table of values:
ID | Pattern | Year |
A23 | Y | 2016 |
D21 | N | 2016 |
A54 | Y | 2016 |
B55 | N | 2016 |
C09 | Y | 2017 |
K01 | M | 2017 |
H11 | N | 2017 |
B11 | N | 2017 |
V87 | N | 2017 |
T31 | M | 2017 |
A62 | Y | 2017 |
Now, "Pattern" has three (3) states (i.e. "Y", "N" and "M") and this is the dilemma:
If I create a column chart that is filtered to show the count of "Y" and "N" entries only, what measure can be built to compute the percentage of either "Y" or "N" to the total "Y" and "N" shown on the chart?
For example, if I add this measure to the Tooltip of the column chart, then hovering over the "Y" bar will show 4 / (4 + 5) = 44.4% and hovering over "N" will show 5 / (4 + 5) = 55.6%.
If I were to get more creative and add a slicer for "Year" and then select "2017", hovering would show 2 / (2 + 3) = 40% and 3 / (2 + 3) = 60% for the "Y" bar and "N" bar respectively.
Any ideas?
Solved! Go to Solution.
In your "Count of ID" in your Values area, click the drop down and then Show as: Percent of Grand Total. Filter your visualization to get rid of M. You should have what you want.
Hi @jmeccles,
You can try to use below formula to get the percent of selected item count.
Measure:
Selected Percent = VAR selected = IF ( HASONEVALUE ( Table[Pattern] ), VALUES ( Table[Pattern] ), BLANK () ) VAR allexceptM = COUNTX ( FILTER ( ALL ( Table ), [Pattern] <> "M" ), [ID] ) RETURN CALCULATE ( COUNT ( Table[ID] ), [Pattern] = selected ) / allexceptM
Regards,
Xiaoxin Sheng
In your "Count of ID" in your Values area, click the drop down and then Show as: Percent of Grand Total. Filter your visualization to get rid of M. You should have what you want.
Thanks, @Greg_Deckler! It's simple and it works, just as I suspected.
And thank you @v-shex-msft. Your solution taught me a few things about the creation and use of variables in Power BI but it just wasn't what I was looking for.
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