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asalazarjr
Frequent Visitor

Percent of Revenue excluding one customer

Hey, Trying to create a measure that gets me customer percent of revenue excluding 1 customer.

The current measure works, but need help filtering the total revenue(minus 1 specific customer).

 

% Revenue =
VAR TotRev= CALCULATE(SUM('Table'[Revenue]),ALL('Table'[Customer List]))
Return
Divide(SUM('Table'[Revenue]),TotRev)
 
Need this to be done in measure so that this new measure excluding 1 customer equals 100%, Any help would be appreciated.


2 ACCEPTED SOLUTIONS
Wendeley-North
Resolver I
Resolver I

% Revenue =
VAR TotRev = CALCULATE ( SUM ('Table'[Revenue]),
                         FILTER ( ALL('Table'[Customer List]), 
                                  'Table'[Customer List] = 'Customer' )
                        )
Return
Divide(SUM('Table'[Revenue]),TotRev)

View solution in original post

% Revenue =
VAR TotRev = CALCULATE ( SUM ('Table'[Revenue]),
                         FILTER ( ALL('Table'[Customer List]), 
                                  'Table'[Customer List] <> 'Customer' )
                        )
Return
Divide(SUM('Table'[Revenue]),TotRev)

Thanks, this is what i was looking for, changed your "=" to  "<>"

View solution in original post

3 REPLIES 3
Wendeley-North
Resolver I
Resolver I

% Revenue =
VAR TotRev = CALCULATE ( SUM ('Table'[Revenue]),
                         FILTER ( ALL('Table'[Customer List]), 
                                  'Table'[Customer List] = 'Customer' )
                        )
Return
Divide(SUM('Table'[Revenue]),TotRev)

View solution in original post

% Revenue =
VAR TotRev = CALCULATE ( SUM ('Table'[Revenue]),
                         FILTER ( ALL('Table'[Customer List]), 
                                  'Table'[Customer List] <> 'Customer' )
                        )
Return
Divide(SUM('Table'[Revenue]),TotRev)

Thanks, this is what i was looking for, changed your "=" to  "<>"

View solution in original post

Ashish_Mathur
Super User
Super User

Hi,

Share some data to work with and also show the expected result.


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/

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