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RonaldvdH
Post Patron
Post Patron

Need help with my formula

Guys, i need some help with my formula because i think im almost there but it still returns an error

Basically i want a measure that calculates that IF [Aantal dgn] <> BLANK then it devides 2 values.

 

Gemiddelde productiviteit LvC =
Divide(
            IF(
                Filter('V&P Civiel LvC';'V&P Civiel LvC'[Aantal dgn]<>BLANK());(
                          SUM('V&P Civiel LvC'[Prognose duur]) / SUM('V&P Civiel LvC'[Aantal dgn])
          )
     )
)
1 ACCEPTED SOLUTION
v-shex-msft
Community Support
Community Support

Hi @RonaldvdH ,

You can try to use below formula if it suitable for your requirement:

Gemiddelde productiviteit LvC =
VAR div1 =
    CALCULATE ( SUM ( Table[Prognose duur] ); Table[Aantal dgn] <> BLANK () )
VAR div2 =
    CALCULATE ( SUM ( Table[Aantal dgn] ); Table[Aantal dgn] <> BLANK () )
RETURN
    IF ( div1 > 0 && div2 > 0; DIVIDE ( div1; div2 ) )

If above not help, can you please share some sample data for test?

Regards,

Xiaoxin Sheng

Community Support Team _ Xiaoxin
If this post helps, please consider accept as solution to help other members find it more quickly.

View solution in original post

8 REPLIES 8
v-shex-msft
Community Support
Community Support

Hi @RonaldvdH ,

You can try to use below formula if it suitable for your requirement:

Gemiddelde productiviteit LvC =
VAR div1 =
    CALCULATE ( SUM ( Table[Prognose duur] ); Table[Aantal dgn] <> BLANK () )
VAR div2 =
    CALCULATE ( SUM ( Table[Aantal dgn] ); Table[Aantal dgn] <> BLANK () )
RETURN
    IF ( div1 > 0 && div2 > 0; DIVIDE ( div1; div2 ) )

If above not help, can you please share some sample data for test?

Regards,

Xiaoxin Sheng

Community Support Team _ Xiaoxin
If this post helps, please consider accept as solution to help other members find it more quickly.

The correct answer was 1,04 so that solved my problem, thanks guys for all your help

Anonymous
Not applicable

Hi @RonaldvdH 

 

If what you want to do is to avoid the error of dividing by 0, just use this formula:

 

Gemiddelde productiviteit LvC = Divide( SUM('V&P Civiel LvC'[Prognose duur]), SUM('V&P Civiel LvC'[Aantal dgn]), 0 )
 
anyway, if you want ot filter the blanks:
 
Gemiddelde productiviteit LvC =
IF( NOT( ISBLANK( SUM('V&P Civiel LvC'[Aantal dgn]) ) ), 
    DIVIDE( SUM('V&P Civiel LvC'[Prognose duur]), SUM('V&P Civiel LvC'[Aantal dgn])
          )
 )
 
santiagomur
Resolver II
Resolver II

emiddelde productiviteit LvC =

            IF(
[Aantal dgn]<>BLANK();
                          SUM('V&P Civiel LvC'[Prognose duur]) / SUM('V&P Civiel LvC'[Aantal dgn]);"were else"
          )
     

 and use as new column

@santiagomur i need this to be a measure is that possible ?

 

Your formula returns an error by the way, the error is roughtly translated into 'the column '[Aantal dgn] cannot be determined, it either does not exist o there is no current row for that column

 

Both arguments are not true because there is a column and it HAS values.

 

i don't know the exactly name of your columns so you need to change, but follow the same arguments. 

if you need measure what i would do first is create the column and then create the  measure you need. 

 

you are trying to validate row by row and as far i know it cant be done with a measure.

 

Gemiddelde productiviteit LvC =

            IF(
[Aantal dgn]<>BLANK();
SUM('V&P Civiel LvC'[Prognose duur]) / SUM('V&P Civiel LvC'[Aantal dgn]);
"were if false if Aantal dgn = Blank" )

 then a measure

total LVC= sum(Gemiddelde productiviteit LvC)

@santiagomur  shouldn't the last measure be an 'average' instead of 'sum' ?

 

total LVC= sum(Gemiddelde productiviteit LvC)

total LVC=average(gemiddelde productiviteit LvC)

 

The sum just returns the total value of the entire colum but i need the average. Obviously ive changed the formula to average and now i get a plausible value but in the answer by @Anonymous the result is different

 

In the formula @santiagomur the average is 1,04 and the formula by @Anonymous  the average is 1,44  

What is the difference between both formula's ?

Anonymous
Not applicable

Hi @RonaldvdH 

 

I don't know exactly what the difference is, so I recommend you to take a sample, do the calculus and check with the result got by both expressions, then you will able to know which one is the correct.

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