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VivianC Frequent Visitor
Frequent Visitor

Median/STDEV For Each Unique Name From Multiple Values

Hello,

I have a table like below. I want to calculate the Median from multiple values  (and Standard Deviation, but here I just show Median as example) based on each unique Key_CountrySkill column:

 

Median.png

 

Stuck here for hours...Can someone help please? Thanks!

1 ACCEPTED SOLUTION

Accepted Solutions
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v-jiascu-msft Super Contributor
Super Contributor

Re: Median/STDEV For Each Unique Name From Multiple Values

Hi @VivianC,

 

You can do it like below. Please also check out the demo in the attachment.

 

Median =
CALCULATE (
    MEDIAN ( Table1[Annualized USD] ),
    ALLEXCEPT ( Table1, Table1[Key_CountrySkill] )
)
Stdev =
CALCULATE (
    STDEV.P ( Table1[Annualized USD] ),
    ALLEXCEPT ( Table1, Table1[Key_CountrySkill] )
)

 

Best Regards,
Dale

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
Highlighted
v-jiascu-msft Super Contributor
Super Contributor

Re: Median/STDEV For Each Unique Name From Multiple Values

Hi @VivianC,

 

You can do it like below. Please also check out the demo in the attachment.

 

Median =
CALCULATE (
    MEDIAN ( Table1[Annualized USD] ),
    ALLEXCEPT ( Table1, Table1[Key_CountrySkill] )
)
Stdev =
CALCULATE (
    STDEV.P ( Table1[Annualized USD] ),
    ALLEXCEPT ( Table1, Table1[Key_CountrySkill] )
)

 

Best Regards,
Dale

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

VivianC Frequent Visitor
Frequent Visitor

Re: Median/STDEV For Each Unique Name From Multiple Values

OMG you are awesome!! Thanks!!!

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