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VivianC Frequent Visitor
Frequent Visitor

Median/STDEV For Each Unique Name From Multiple Values

Hello,

I have a table like below. I want to calculate the Median from multiple values  (and Standard Deviation, but here I just show Median as example) based on each unique Key_CountrySkill column:

 

Median.png

 

Stuck here for hours...Can someone help please? Thanks!

1 ACCEPTED SOLUTION

Accepted Solutions
Community Support Team
Community Support Team

Re: Median/STDEV For Each Unique Name From Multiple Values

Hi @VivianC,

 

You can do it like below. Please also check out the demo in the attachment.

 

Median =
CALCULATE (
    MEDIAN ( Table1[Annualized USD] ),
    ALLEXCEPT ( Table1, Table1[Key_CountrySkill] )
)
Stdev =
CALCULATE (
    STDEV.P ( Table1[Annualized USD] ),
    ALLEXCEPT ( Table1, Table1[Key_CountrySkill] )
)

 

Best Regards,
Dale

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
2 REPLIES 2
Community Support Team
Community Support Team

Re: Median/STDEV For Each Unique Name From Multiple Values

Hi @VivianC,

 

You can do it like below. Please also check out the demo in the attachment.

 

Median =
CALCULATE (
    MEDIAN ( Table1[Annualized USD] ),
    ALLEXCEPT ( Table1, Table1[Key_CountrySkill] )
)
Stdev =
CALCULATE (
    STDEV.P ( Table1[Annualized USD] ),
    ALLEXCEPT ( Table1, Table1[Key_CountrySkill] )
)

 

Best Regards,
Dale

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
VivianC Frequent Visitor
Frequent Visitor

Re: Median/STDEV For Each Unique Name From Multiple Values

OMG you are awesome!! Thanks!!!